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Identify the chirality centers in the compound (2R,3S)-butanedioic acid and draw all possible stereoisomers. Determine which of the stereoisomers is the enantiomer of (2R,3S)-butanedioic acid.

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2R,3S -butanedioic acid has two chirality centers: C2 and C3. The IUPAC name for this compound is  2R,3S -2,3-dihydroxybutanedioic acid. The structure of this compound is as follows:HOOC-CH OH -CH OH -COOHTo draw all possible stereoisomers, we need to consider the different configurations at both chirality centers. There are 2^2 = 4 possible stereoisomers:1.  2R,3S -butanedioic acid: HOOC-CH OH -CH OH -COOH2.  2S,3S -butanedioic acid: HOOC-CH OH -CH OH -COOH3.  2R,3R -butanedioic acid: HOOC-CH OH -CH OH -COOH4.  2S,3R -butanedioic acid: HOOC-CH OH -CH OH -COOHThe enantiomer of  2R,3S -butanedioic acid is the molecule with the opposite configuration at both chirality centers. In this case, the enantiomer is  2S,3R -butanedioic acid.
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