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Calculate the standard electrode potential for the following redox reaction in acidic medium using the standard reduction potentials given below:Fe<sup>2+</sup>(aq) + MnO<sub>4</sub><sup>-</sup>(aq) + H<sup>+</sup>(aq) → Fe<sup>3+</sup>(aq) + Mn<sup>2+</sup>(aq) + H<sub>2</sub>O(l)Standard reduction potentials:Fe<sup>3+</sup>(aq) + e<sup>-</sup> → Fe<sup>2+</sup>(aq) E<sub>o</sub> = +0.77 VMnO<sub>4</sub><sup>-</sup>(aq) + 8H<sup>+</sup>(aq) + 5e<sup>-</sup> → Mn<sup>2+</sup>(aq) + 4H<sub>2</sub>O(l) E<sub>o</sub> = +1.51 V
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