Answers by ShayneMolina

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Calculate the standard enthalpy change for the precipitation reaction that occurs when 100 mL of 0.2 M lead nitrate solution reacts with 100 mL of 0.1 M sodium iodide solution to form solid lead iodide and aqueous sodium nitrate. The balanced chemical equation for the reaction is:Pb(NO3)2(aq) + 2 NaI(aq) → PbI2(s) + 2 NaNO3(aq)Given: - Molar mass of Pb(NO3)2 = 331.20 g/mol - Molar mass of NaI = 149.89 g/mol - Density of 0.2 M lead nitrate solution = 1.055 g/mL - Density of 0.1 M sodium iodide solution = 1.04 g/mL - Specific heat capacity of the reaction mixture is 4.18 J/(g · °C) - The initial temperature of the reaction mixture and the surroundings is 25 °C.

answered 2 days ago in Chemical thermodynamics

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