Answers by JerriPrichar

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Calculate the standard enthalpy change of the reaction below at 298K.Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)Given the following standard enthalpies of formation (ΔHf°):ΔHf°[Fe2O3(s)] = -824.2 kJ/molΔHf°[Fe(s)] = 0 kJ/molΔHf°[CO(g)] = -110.5 kJ/molΔHf°[CO2(g)] = -393.5 kJ/mol. Also, calculate the change in standard entropy of the system (ΔS°) and determine whether the reaction is spontaneous or not.

answered Feb 3 in Inorganic Chemistry

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