Answers by JamieHardacr

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Calculate the standard enthalpy change (∆H°) for the reaction: 2NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l)Given the following bond dissociation energies (in kJ/mol):N≡N = 941, N-H = 391, O=O = 495, O-H = 464, N-O = 201, H-O-H = 464, N-H + O=O = 632, N=O = 607, and H-N≡N = 945.

answered 2 days ago in Quantum Chemistry

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answered Jan 20 in Psychology

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answered Jan 16 in Psychology

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answered Jan 8 in Science

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answered Dec 30, 2024 in Science

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