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Calculate the potential difference between two silver electrodes that are placed into a solution containing 0.1M of AgNO3 and a current of 2.5 A is passed through the cell. The polarization caused by the passage of current through the cell is found to be 0.2 V. Given that the standard reduction potential of Ag+ to Ag is 0.80 V, calculate the equilibrium potential of the cell.
asked
Feb 3
in
ElectroChemistry
by
CatherineMcc
(
2.5k
points)
0
votes
1
answer
59
views
Calculate the polarization that occurs in an electrochemical cell when a current of 2 A flows through it for 10 minutes. The electrode area is 25 cm², and the current efficiency is 95%. The activation energy is 80 kJ/mol, and the reaction quotient is 2.5 x 10⁻⁵. The temperature of the cell is 25°C. Find the polarization resistance and the total polarization of the cell.
asked
Feb 3
in
ElectroChemistry
by
AleciaAlleyn
(
1.5k
points)
0
votes
1
answer
76
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Calculate the polarization resistance of a copper electrode in a 0.1 M copper sulfate solution at 25°C, given that the current density is 10 mA/cm² and the exchange current density is 0.1 mA/cm². The Tafel slope is 30 mV/decade.
asked
Feb 3
in
ElectroChemistry
by
HeidiElmslie
(
1.8k
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0
votes
1
answer
75
views
Calculate the polarization potential in an electrochemical cell if the concentration of zinc ions in the anode compartment is 0.5 M, the concentration of copper(II) ions in the cathode compartment is 1.0 M, and the voltage of the cell is 1.1 V. The standard reduction potential of copper(II) ions is +0.34 V and the standard reduction potential of zinc ions is -0.76 V.
asked
Feb 3
in
ElectroChemistry
by
HesterLoyau3
(
2.1k
points)
0
votes
1
answer
75
views
Calculate the polarization of a copper-silver galvanic cell in which the concentration of copper ions is 0.5 M, the concentration of silver ions is 0.1 M, and the cell is operating at a temperature of 25°C. The potential difference of the cell is measured to be 0.75 V.
asked
Feb 3
in
ElectroChemistry
by
VioletteM27
(
2.1k
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0
votes
1
answer
43
views
Calculate the polarization of a copper electrode immersed in a 0.1 M CuSO4 solution at 25°C when it is coupled to a hydrogen electrode with a hydrogen pressure of 1 atm. Given that the standard reduction potential of Cu2+|Cu electrode is 0.34 V and the standard reduction potential of H+|H2 electrode is 0 V at 25°C.
asked
Feb 3
in
ElectroChemistry
by
JadaMeece33
(
1.6k
points)
0
votes
1
answer
64
views
Calculate the polarization of a cell having an anode made of copper metal immersed in a 1.0 M Cu(NO3)2 solution and a cathode made of silver metal in a 1.0 M AgNO3 solution. Given that the potential of the copper electrode is -0.34 V and that of the silver electrode is 0.80 V. Also, assume that the current density is 0.1 A/cm² and that the temperature is 298 K.
asked
Feb 3
in
ElectroChemistry
by
JaimeFuqua07
(
2.0k
points)
0
votes
1
answer
58
views
Calculate the polarization in an electrochemical cell consisting of a zinc electrode and a copper electrode. The electrode potentials of zinc and copper are -0.76 V and +0.34 V, respectively. The resistance of the electrolyte solution between the electrodes is 10 ohms, and the current flowing through the cell is 0.5 A.
asked
Feb 3
in
ElectroChemistry
by
ClydeC545764
(
2.2k
points)
0
votes
1
answer
66
views
Calculate the pH of a solution with a concentration of 0.01 M HCl.
asked
Feb 3
in
Chemical reactions
by
AHIKayleigh
(
2.3k
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0
votes
1
answer
50
views
Calculate the pH of a buffer solution that contains 0.2 moles of acetic acid (CH3COOH) and 0.1 moles of sodium acetate (NaCH3COO) dissolved in one liter of solution. The dissociation constant of acetic acid is 1.8 x 10^-5.
asked
Feb 3
in
Chemical reactions
by
EdytheEwk100
(
2.6k
points)
0
votes
1
answer
42
views
Calculate the pH of a buffer solution made by combining equal volumes of 0.1 M acetic acid and 0.1 M sodium acetate. The dissociation constant of acetic acid is 1.8 × 10^-5.
asked
Feb 3
in
Chemical reactions
by
LuzMccrary7
(
2.5k
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0
votes
1
answer
56
views
Calculate the pH of a buffer solution consisting of 0.1 M acetic acid and 0.1 M sodium acetate, given that the dissociation constant (Ka) of acetic acid is 1.8x10^-5.
asked
Feb 3
in
Chemical reactions
by
TwylaArledge
(
1.6k
points)
0
votes
1
answer
63
views
Calculate the pH of a 0.2 M solution of acetic acid (Ka = 1.8 x 10^-5) at 25°C.
asked
Feb 3
in
Chemical reactions
by
Lizzie32E683
(
1.8k
points)
0
votes
1
answer
56
views
Calculate the pH of a 0.2 M solution of acetic acid (CH3COOH) if the acid dissociation constant (Ka) of acetic acid is 1.8 × 10^-5.
asked
Feb 3
in
Chemical reactions
by
Beatris09Q13
(
1.9k
points)
0
votes
1
answer
62
views
Calculate the pH of a 0.1 M solution of hydrochloric acid assuming complete dissociation. The acid dissociation constant (Ka) for HCl is 1.3 × 10^-6 at 25°C.
asked
Feb 3
in
Chemical reactions
by
LeeAlder0448
(
1.5k
points)
0
votes
1
answer
51
views
Calculate the pH of a 0.1 M solution of hydrochloric acid (HCl) assuming complete dissociation of the acid in water, and identify if the solution is acidic, basic or neutral.
asked
Feb 3
in
Inorganic Chemistry
by
EmilySulman6
(
2.0k
points)
0
votes
1
answer
50
views
Calculate the pH of a 0.1 M solution of acetic acid with a dissociation constant (Ka) of 1.8 x 10^-5.
asked
Feb 3
in
Chemical reactions
by
JaneAlbrecht
(
1.9k
points)
0
votes
1
answer
63
views
Calculate the pH of a 0.1 M solution of acetic acid (Ka = 1.8 x 10^-5).
asked
Feb 3
in
Chemical reactions
by
MorrisMcGahe
(
1.7k
points)
0
votes
1
answer
56
views
Calculate the pH of a 0.1 M solution of acetic acid (CH3COOH) given that its dissociation constant Ka is 1.8x10^-5.
asked
Feb 3
in
Chemical reactions
by
LorenaReinha
(
1.8k
points)
0
votes
1
answer
64
views
Calculate the percentage change in the concentration of reactants and products in a chemical equilibrium when the concentration of a common ion is increased by 0.1M. The equilibrium constant for the reaction is Kc = 1.5 x 10^-5 M at a certain temperature.
asked
Feb 3
in
Chemical equilibrium
by
DarylBottoml
(
2.0k
points)
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