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Calculate the standard enthalpy change (in kJ/mol) for the following reaction involving solutions: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)Given the following enthalpy values:NaOH(aq): -469.2 kJ/mol HCl(aq): -167.2 kJ/mol NaCl(aq): -411.2 kJ/mol H2O(l): -285.8 kJ/mol

asked Feb 3 in Chemical thermodynamics by MuhammadNuna (2.1k points)

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Calculate the standard enthalpy change (in kJ/mol) for the following chemical reaction at 298 K:2SO2(g) + O2(g) → 2SO3(g)Given the standard enthalpies of formation (∆Hf°) at 298 K for SO2(g), O2(g), and SO3(g) are -296.8 kJ/mol, 0 kJ/mol, and -396.0 kJ/mol, respectively.

asked Feb 3 in Physical Chemistry by ClarkPuig93 (2.0k points)

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Calculate the standard enthalpy change (in kJ/mol) for the dissolution of 3.50 g of potassium hydroxide (KOH) in 250.0 mL of water at 25°C, given that the molar heat of solution of KOH is -57.61 kJ/mol.

asked Feb 3 in Chemical thermodynamics by CharleneLemu (1.7k points)

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Calculate the standard enthalpy change (∆H°) of combustion for methane gas (CH4) given that the heat of formation (∆Hf°) for methane is -74.87 kJ/mol and the heat of formation (∆Hf°) for carbon dioxide (CO2) is -393.51 kJ/mol, and the heat of formation (∆Hf°) for water (H2O) is -285.83 kJ/mol.

asked Feb 3 in Chemical thermodynamics by StanGjo3033 (1.9k points)

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Calculate the standard enthalpy change (∆H°) for the vaporization of 10 grams of water at 100°C, given that the molar heat of vaporization of water is 40.7 kJ/mol.

asked Feb 3 in Chemical thermodynamics by MelbaTulloch (2.2k points)

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Calculate the standard enthalpy change (∆H°) for the reaction: NaOH(aq) + HCl(aq) -> NaCl(aq) + H2O(l) given the following information: - The enthalpy change of neutralization of HCl(aq) with NaOH(aq) is -55.9 kJ/mol. - The enthalpy of formation of NaCl(s) is -411.2 kJ/mol.- The enthalpy of vaporization of water (H2O) is 40.7 kJ/mol.Assume that the specific heat capacity of the water is 4.18 J/g K and the density of the solution is 1 g/mL.

asked Feb 3 in Chemical thermodynamics by PeggyBednall (1.9k points)

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Calculate the standard enthalpy change (∆H°) for the reaction: 2HCl(aq) + Na2CO3(aq) → CO2(g) + H2O(l) + 2NaCl(aq) given that the standard enthalpy of formation (∆H°f) for NaCl(aq), H2O(l) and CO2(g) are -407.3 kJ/mol, -285.8 kJ/mol and -393.5 kJ/mol respectively.

asked Feb 3 in Chemical thermodynamics by RyderShupe77 (1.7k points)

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Calculate the standard enthalpy change (∆H°) for the reaction: 2NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l)Given the following bond dissociation energies (in kJ/mol):N≡N = 941, N-H = 391, O=O = 495, O-H = 464, N-O = 201, H-O-H = 464, N-H + O=O = 632, N=O = 607, and H-N≡N = 945.

asked Feb 3 in Quantum Chemistry by Phillipp57B1 (2.3k points)

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Calculate the standard enthalpy change (∆H°) for the reaction that involves the formation of complex [Fe(H2O)6]Cl3 from its constituent ions, given the following information: Fe3+(aq) + 6H2O(l) ⇌ [Fe(H2O)6]3+ ∆Hf° = +123 kJ/mol Cl-(aq) ∆Hf° = -167 kJ/mol

asked Feb 3 in Chemical thermodynamics by ClarkFogarty (1.9k points)

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Calculate the standard enthalpy change (∆H°) for the reaction of the coordination compound [Co(NH3)6]Cl3 (aq) with NaOH (aq) to produce [Co(NH3)6](OH)3 (aq) and NaCl (aq). Given, the standard enthalpy of formation (∆H°f) for [Co(NH3)6]Cl3, [Co(NH3)6](OH)3 and NaCl are -784.8 kJ/mol, -1273.6 kJ/mol and -411.2 kJ/mol, respectively.

asked Feb 3 in Chemical thermodynamics by Vernell30C7 (2.5k points)

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Calculate the standard enthalpy change (∆H°) for the reaction between 50.0 mL of 0.100 M hydrochloric acid (HCl) and 50.0 mL of 0.100 M sodium hydroxide (NaOH), given that the temperature change was -5.01°C and the specific heat capacity of the solution is 4.18 J/g°C. The balanced chemical equation for the reaction is:HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)Note: Assume the density of the solutions is 1.00 g/mL and that the specific heat capacity of the solutions is the same as that of water.

asked Feb 3 in Chemical thermodynamics by Mose2866156 (1.6k points)

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Calculate the standard enthalpy change (∆H°) for the reaction between 25.0 mL of 0.100 M HCl and 25.0 mL of 0.100 M NaOH at 25°C. The density of each solution is 1.00 g/mL and the heat capacity of the solution is 4.18 J/g·°C. The reaction takes place in a calorimeter, and the temperature increase is measured to be 8.47°C.

asked Feb 3 in Chemical thermodynamics by BobBar745884 (1.9k points)

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Calculate the standard enthalpy change (∆H°) for the precipitation reaction between aqueous solutions of silver nitrate (AgNO3) and sodium chloride (NaCl) to form solid silver chloride (AgCl), given that 50.0 mL of 0.100 M AgNO3 and 50.0 mL of 0.100 M NaCl were combined in a calorimeter and the temperature change was recorded as -2.5°C.

asked Feb 3 in Chemical thermodynamics by JodieBaskett (1.8k points)

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1 answer 71 views

Calculate the standard enthalpy change (∆H°) for the precipitation reaction between aqueous solutions of lead(II) nitrate [Pb(NO3)2] and potassium iodide (KI) producing solid lead(II) iodide (PbI2) and aqueous potassium nitrate (KNO3) at a temperature of 25°C.

asked Feb 3 in Chemical thermodynamics by KaraGass5143 (2.3k points)

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Calculate the standard enthalpy change (∆H°) for the neutralization reaction of 50.0 mL of 0.100 M HCl with 75.0 mL of 0.0750 M NaOH at a constant pressure of 1 atm and a temperature of 25°C.

asked Feb 3 in Chemical thermodynamics by AngeliaDewey (1.8k points)

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Calculate the standard enthalpy change (∆H°) for the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) given the following information:- Balanced chemical equation: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)- ∆H°f of NaCl(aq) = -407.3 kJ/mol- ∆H°f of H2O(l) = -285.8 kJ/mol- Heat capacity of the system, Cp = 4.18 J/g.K- Mass of the HCl solution used = 50.0 g- Concentration of HCl solution = 0.100 M- Volume of NaOH solution used = 100.0 mL- Concentration of NaOH solution = 0.200 MAssume that the specific heat of the solution is equal to that of water at 4.18 J/g.K and that the density o

asked Feb 3 in Chemical thermodynamics by HughNewquist (2.3k points)

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1 answer 60 views

Calculate the standard enthalpy change (∆H°) for the formation of ammonia (NH3) at 298 K using the following data: N2(g) + 3H2(g) → 2NH3(g) ∆H° = −92.4 kJ/mol Hint: Standard enthalpy change (∆H°) for a reaction is calculated by taking the sum of the standard enthalpies of the products minus the sum of the standard enthalpies of the reactants.

asked Feb 3 in Chemical thermodynamics by CathrynMacMa (2.5k points)

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1 answer 64 views

Calculate the standard enthalpy change (∆H°) for the following reaction involving liquids:C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (l)

asked Feb 3 in Chemical thermodynamics by FinleySalern (1.6k points)

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Calculate the standard enthalpy change (∆H°) for the dissolution reaction of 5.00 grams of sodium chloride (NaCl) in 100.0 mL of water, given that the final temperature of the solution was 25.0°C and the heat capacity of the solution was 4.18 J/g°C. The molar mass of NaCl is 58.44 g/mol and the density of water is 1.00 g/mL.

asked Feb 3 in Chemical thermodynamics by VallieSwaffo (1.7k points)

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Calculate the standard enthalpy change (∆H°) for the dissolution of 5.00 g of solid NaOH in 100.0 mL of water, given that the temperature of the solution increased from 25.0°C to 27.5°C. The density of the solution is 1.00 g/mL and the specific heat capacity of the solution is 4.18 J/(g°C). The molar mass of NaOH is 40.00 g/mol.

asked Feb 3 in Chemical thermodynamics by ModestaDavey (1.6k points)

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