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Calculate the standard enthalpy change for the reaction: 2Fe(s) + 3/2O2(g) → Fe2O3(s), given that the standard enthalpy of formation for Fe2O3(s) is -824.2 kJ/mol, the standard enthalpy of formation for Fe(s) is 0 kJ/mol, and the standard enthalpy of formation for O2(g) is 0 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
BroderickHom
(
2.1k
points)
0
votes
1
answer
60
views
Calculate the standard enthalpy change for the reaction: Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) Given the following standard enthalpy of formation values: ΔHf° [Fe2O3(s)] = -824 kJ/mol ΔHf° [CO(g)] = -110 kJ/mol ΔHf° [CO2(g)] = -393.5 kJ/mol ΔHf° [Fe(s)] = 0 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
CarrieMadiso
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1.8k
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0
votes
1
answer
68
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Calculate the standard enthalpy change for the reaction: C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l), given the following standard enthalpies of formation: ΔHf°[C2H5OH(l)] = -277.69 kJ/mol, ΔHf°[CO2(g)] = -393.51 kJ/mol, ΔHf°[H2O(l)] = -285.83 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
JanellLunsfo
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2.0k
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0
votes
1
answer
72
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Calculate the standard enthalpy change for the reaction: 2 NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2 H2O(l)Given the following data:ΔHf°(NaOH) = -469.14 kJ/molΔHf°(H2SO4) = -814.00 kJ/molΔHf°(Na2SO4) = -1388.40 kJ/molΔHf°(H2O(l)) = -285.83 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
BetteBoniwel
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1.6k
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0
votes
1
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49
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Calculate the standard enthalpy change for the reaction: 2 Al(s) + 3/2 O2(g) → Al2O3(s) given the following information: ΔH°f[Al2O3(s)] = -1676.0 kJ/mol ΔH°f[Al(s)] = 0 kJ/mol ΔH°f[O2(g)] = 0 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
AmeliaCuella
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1.8k
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0
votes
1
answer
55
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Calculate the standard enthalpy change for the reaction: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l) Given the following information: ΔHf° [NaOH(aq)] = -469.1 kJ/mol ΔHf° [HCl(aq)] = -167.2 kJ/mol ΔHf° [NaCl(aq)] = -407.3 kJ/mol ΔHf° [H2O(l)] = -286 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
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MacLgq130601
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2.4k
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0
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1
answer
48
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Calculate the standard enthalpy change for the reaction: CuSO4 (aq) + 4NH3 (aq) -> Cu(NH3)4SO4 (aq) given that the standard enthalpy changes of formation for CuSO4 (aq) and NH3 (aq) are -771.5 kJ/mol and -46.19 kJ/mol respectively, and the standard enthalpy change of formation for Cu(NH3)4SO4 (aq) is -2130.4 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
VickeyPeacoc
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2.4k
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0
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1
answer
65
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Calculate the standard enthalpy change for the reaction: CH4(g) + 2O2(g) -> CO2(g) + 2H2O(g) Given the necessary bond enthalpies are: C-H = 411 kJ/molO=O = 495 kJ/molO-H = 463 kJ/molC=O = 799 kJ/mol.
asked
Feb 3
in
Quantum Chemistry
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CathrynMacMa
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2.5k
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0
votes
1
answer
58
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Calculate the standard enthalpy change for the reaction: CH3OH (l) + 3/2 O2 (g) -> CO2 (g) + 2H2O (l) given the standard enthalpies of formation for CH3OH (l), CO2 (g) and H2O (l) as -238.6 kJ/mol, -393.5 kJ/mol and -285.8 kJ/mol respectively.
asked
Feb 3
in
Chemical thermodynamics
by
Rosaline02Y
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2.0k
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0
votes
1
answer
60
views
Calculate the standard enthalpy change for the reaction: C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (l)Given the following standard enthalpies of formation: ΔHf(C6H12O6 (s)) = -1273 kJ/molΔHf(CO2 (g)) = -393.5 kJ/molΔHf(H2O (l)) = -285.8 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
SelenaRonan
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2.2k
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0
votes
1
answer
59
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Calculate the standard enthalpy change for the reaction: 2NaOH (s) + H2SO4 (aq) → Na2SO4 (aq) + 2H2O (l)given that the standard enthalpy of formation of Na2SO4 (aq) is -1385 kJ/mol, and the standard enthalpies of formation of NaOH (s), H2SO4 (aq) and H2O (l) are -425 kJ/mol, -814 kJ/mol and -286 kJ/mol respectively.
asked
Feb 3
in
Chemical thermodynamics
by
FrancescaTor
(
2.0k
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0
votes
1
answer
55
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Calculate the standard enthalpy change for the reaction: 2H2(g) + O2(g) → 2H2O(l)Given the standard enthalpies of formation are: ΔHf°(H2O(l)) = -285.8 kJ/mol ΔHf°(H2(g)) = 0 kJ/mol ΔHf°(O2(g)) = 0 kJ/mol Assume all reactants and products are at standard state conditions.
asked
Feb 3
in
Chemical thermodynamics
by
SimonMcWilli
(
1.9k
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0
votes
1
answer
68
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Calculate the standard enthalpy change for the reaction: 2H2(g) + O2(g) --> 2H2O(l)Given the following enthalpies of formation: ∆Hf°(H2O, l) = -285.8 kJ/mol ∆Hf°(H2, g) = -241.8 kJ/mol ∆Hf°(O2, g) = 0 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
NevaBrooks50
(
1.7k
points)
0
votes
1
answer
70
views
Calculate the standard enthalpy change for the reaction: 2Fe(s) + 3/2 O2(g) -> Fe2O3(s) given that the standard enthalpy of formation for Fe2O3(s) is -824.2 kJ/mol and that of Fe(s) is 0 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
JackH2065356
(
1.1k
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0
votes
1
answer
40
views
Calculate the standard enthalpy change for the reaction: 2C2H5OH(l) + 9O2(g) -> 6CO2(g) + 8H2O(l) given that the standard enthalpy of formation for C2H5OH(l) is -278 kJ/mol, for CO2(g) is -394 kJ/mol and for H2O(l) is -286 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
IolaHolly818
(
2.0k
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0
votes
1
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45
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Calculate the standard enthalpy change for the reaction: [Cu(H2O)6]2+(aq) + 2NH3(aq) → [Cu(NH3)4(H2O)2]2+(aq) + 4H2O(l)given the following information: ΔHf° [Cu(H2O)6]2+(aq) = -203.2 kJ/molΔHf° [Cu(NH3)4(H2O)2]2+(aq) = -368.5 kJ/molΔHf° H2O(l) = -285.8 kJ/molΔHf° NH3(aq) = -80.8 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
LionelBonney
(
2.0k
points)
0
votes
1
answer
55
views
Calculate the standard enthalpy change for the reaction: [Co(H2O)6]2+(aq) + 4Cl-(aq) → [CoCl4]2-(aq) + 6H2O(l) Given the following information:• ΔH°f of [Co(H2O)6]2+ is 32.3 kJ/mol • ΔH°f of [CoCl4]2- is -341.8 kJ/mol • ΔH°f of H2O(l) is -285.8 kJ/mol • The ΔH°f of Cl- is taken as zero
asked
Feb 3
in
Chemical thermodynamics
by
SommerBartos
(
1.8k
points)
0
votes
1
answer
69
views
Calculate the standard enthalpy change for the reaction where 50 ml of 0.1 M hydrochloric acid reacts with 50 ml of 0.1 M sodium hydroxide solution. The temperature change observed during the reaction was 5°C and the specific heat capacity of the solution is 4.18 J/g°C.
asked
Feb 3
in
Chemical thermodynamics
by
PriscillaLaf
(
1.6k
points)
0
votes
1
answer
66
views
Calculate the standard enthalpy change for the reaction where 3 moles of hydrogen gas react with 1 mole of nitrogen gas to form 2 moles of ammonia gas. Given the following thermochemical equation: N2(g) + 3 H2(g) → 2 NH3(g) ΔH° = −92.4 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
MamieSanmigu
(
1.8k
points)
0
votes
1
answer
71
views
Calculate the standard enthalpy change for the reaction where 250 mL of 2M HCl is mixed with 500 mL of 1M NaOH, assuming that the specific heat capacity of the resulting solution is 4.18 J/g°C and the density of the solution is 1.00 g/mL. (Hint: The balanced chemical equation for the reaction is HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l))
asked
Feb 3
in
Chemical thermodynamics
by
FerneSparks
(
2.3k
points)
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