Recent questions in Chemistry

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Calculate the equilibrium constant, Kc, for the reaction below at 25°C if the concentration of CO2 is 1.2 M, the concentration of H2 is 0.8 M and the concentration of CO is 0.6 M.CO2(g) + H2(g) ⇌ CO(g) + H2O(g)

asked Jan 23 in Chemical equilibrium by HowardNavarr (350 points)

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Calculate the equilibrium constant, Kc, at 298 K for the reaction 2 SO2(g) + O2(g) ⇌ 2 SO3(g) when the initial concentrations of SO2, O2, and SO3 are 0.100 M, 0.200 M, and 0.300 M, respectively.

asked Jan 23 in Chemical equilibrium by LaurelFeuers (310 points)

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Calculate the equilibrium constant, Ka, for the dissociation of a weak acid HA with an initial concentration of 0.10 M that ionizes to form H+ and A-. At equilibrium, the concentration of H+ is found to be 1.0 x 10^-5 M and the concentration of A- is 0.09 M.

asked Jan 23 in Chemical equilibrium by Dominic1066 (250 points)

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Calculate the equilibrium constant, K, for the electrochemical reaction below, given the standard reduction potentials at 298 K:2 H+ (aq) + 2 e- → H2 (g) E° = 0.00 VFe3+ (aq) + e- → Fe2+ (aq) E° = +0.771 V

asked Jan 23 in ElectroChemistry by Lucienne86O (250 points)

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Calculate the equilibrium constant for the reaction: 2 NOCl(g) ⇌ 2 NO(g) + Cl2(g) if at equilibrium the concentrations are [NOCl] = 0.050 M, [NO] = 0.030 M, and [Cl2] = 0.020 M.

asked Jan 23 in Chemical equilibrium by MeghanDalton (250 points)

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1 answer 61 views

Calculate the equilibrium constant for the reaction that occurs when a copper electrode is placed in a solution of 0.1 M copper(II) sulfate and connected to a standard hydrogen electrode. The cell potential at standard conditions is observed to be 0.34 V. (Hint: Use the Nernst equation to relate the cell potential to the equilibrium constant.)

asked Jan 23 in ElectroChemistry by QAIElke25407 (270 points)

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1 answer 67 views

Calculate the equilibrium constant for the reaction 2 SO2(g) + O2(g) ⇌ 2 SO3(g), given that the concentrations at equilibrium are [SO2] = 0.20 M, [O2] = 0.30 M and [SO3] = 0.50 M.

asked Jan 23 in Chemical equilibrium by NellMtg43094 (970 points)

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1 answer 55 views

Calculate the equilibrium constant for the following electrochemical reaction at a temperature of 25°C:$$\ce{Co^{2+} + 2e^- <=> Co(s)}$$Given that the standard reduction potential for the half-reaction is $-0.28\,\text{V}$ and the concentration of $\ce{Co^{2+}}$ is $0.1\,\text{M}$.

asked Jan 23 in ElectroChemistry by ZoilaL75412 (290 points)

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Calculate the equilibrium constant for the following electrochemical reaction at 298K:$$\ce{2Fe^3+ (aq) + 2I^- (aq) -> 2Fe^2+ (aq) + I2 (s)}$$ Given: Standard reduction potentials: $\ce{Fe^3+ + e^- -> Fe^2+}$ Eº = +0.77V $\ce{2I^- -> I2 + 2e^- }$ Eº = +0.54V

asked Jan 23 in ElectroChemistry by Darlene7388 (310 points)

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Calculate the equilibrium constant for the following electrochemical cell reaction at 25°C:Cu(s) + 2 Ag+(aq) --> Cu2+(aq) + 2 Ag(s)Given the standard reduction potentials are:Cu2+(aq) + 2 e- → Cu(s) E°red = +0.34 VAg+(aq) + 1 e- → Ag(s) E°red = +0.80 V

asked Jan 23 in ElectroChemistry by LuellaNorthm (530 points)

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1 answer 63 views

Calculate the equilibrium constant for the electrochemical reaction: Zn(s) + 2H^+(aq) → Zn^2+(aq) + H2(g) when the concentration of Zn^2+ is 0.25 M, [H^+] is 2.5 × 10^-3 M, and the pressure of H2 is 0.8 atm at 298 K.

asked Jan 23 in ElectroChemistry by ShelaGabriel (490 points)

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Calculate the equilibrium constant for the electrochemical cell reaction given below, if the standard reduction potential for the reduction of Fe3+ ion is -0.771 V and for the reduction of Ag+ ion is +0.799 V. Fe3+ + 3e- → Fe (s) E° = -0.771 VAg+ + e- → Ag (s) E° = +0.799 V

asked Jan 23 in ElectroChemistry by JennieCasas0 (290 points)

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1 answer 55 views

Calculate the equilibrium constant for a reaction involving a weak oxidizing agent where the concentration of the oxidizing agent is 0.1 M and the concentration of the reduced species is 0.05 M at equilibrium. The balanced chemical equation of the reaction is given as follows:OX + 2 e- ⇌ REDwhere OX is the weak oxidizing agent and RED is the reduced species.

asked Jan 23 in Chemical equilibrium by FayNzg881763 (310 points)

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Calculate the equilibrium constant at 25°C for the reaction: CO(g) + 3H2(g) ⇌ CH4(g) + H2O(g) If at equilibrium, the concentration of CO is 0.10 M, H2 is 0.20 M, CH4 is 0.015 M and H2O is 0.035 M.

asked Jan 23 in Chemical equilibrium by TylerRobin60 (430 points)

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1 answer 64 views

Calculate the equilibrium constant (Kc) of the reaction below at 25°C with and without a catalyst and determine the effect of the catalyst on the equilibrium position.N2(g) + 3H2(g) ⇄ 2NH3(g)

asked Jan 23 in Chemical equilibrium by BridgettFait (190 points)

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1 answer 61 views

Calculate the equilibrium constant (Kc) of the chemical reaction: 2NOCl(g) ⇌ 2NO(g) + Cl2(g) where the concentration of NOCl is 0.5 M, NO is 0.2 M, and Cl2 is 0.1 M at equilibrium at a certain temperature.

asked Jan 23 in Chemical reactions by ZVSLourdes7 (470 points)

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1 answer 54 views

Calculate the equilibrium constant (Kc) for the reaction: 2A(g) + B(g) ⇌ C(g) + D(g), if the concentration of A is 0.25 M, the concentration of B is 0.10 M, the concentration of C is 0.30 M and the concentration of D is 0.20 M at equilibrium.

asked Jan 23 in Chemical thermodynamics by MarianoPento (390 points)

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1 answer 67 views

Calculate the equilibrium constant (Kc) for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g) if the equilibrium concentration of nitrogen (N2) is 0.025 M, hydrogen (H2) is 0.10 M, and ammonia (NH3) is 0.015 M.

asked Jan 23 in Chemical reactions by ErnaPitt1143 (250 points)

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Calculate the equilibrium constant (Kc) for the reaction between nitrogen gas (N2) and hydrogen gas (H2) to form ammonia gas (NH3) at a temperature of 400 K. The reaction is written as follows: N2(g) + 3H2(g) ⇌ 2NH3(g) Given the equilibrium concentrations are [N2] = 0.10 M, [H2] = 0.20 M, and [NH3] = 1.0 M.

asked Jan 23 in Chemical thermodynamics by MilagroEads3 (390 points)

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Calculate the equilibrium constant (Kc) for the reaction between iodine (I2) and potassium iodide (KI) in an aqueous solution, given that at equilibrium, the concentration of iodine is 0.008 M and the concentration of potassium iodide is 0.15 M. The balanced equation for the reaction is given below:I2 (aq) + 2KI (aq) ⇌ 2K+ (aq) + 2I- (aq)

asked Jan 23 in Chemical equilibrium by PaulinaTalbo (150 points)

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