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Recent questions in Chemical thermodynamics
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1
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Calculate the standard free energy change (ΔG°) for the following redox reaction at 298K:Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s) (Given: E°cell = 1.10V, F = 96,500 J/V.mol)
asked
Feb 3
in
Chemical thermodynamics
by
TraciCoomes1
(
1.9k
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0
votes
1
answer
56
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Calculate the standard free energy change (ΔG°) for the following redox reaction at 298 K, given that E°cell = 0.91 V:Zn(s) + 2 Ag+(aq) → Zn2+(aq) + 2 Ag(s)
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Feb 3
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Chemical thermodynamics
by
ScottyWild8
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1.4k
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0
votes
1
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68
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Calculate the standard free energy change (ΔG°) for the following reaction at 25°C: 2Fe2+(aq) + Cu2+(aq) -> 2Fe3+(aq) + Cu+(aq) (Standard reduction potentials: Fe3+(aq) + e- -> Fe2+(aq) E° = 0.77 V Cu2+(aq) + e- -> Cu+(aq) E° = 0.16 V)
asked
Feb 3
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Chemical thermodynamics
by
LovieCastles
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2.3k
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0
votes
1
answer
57
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Calculate the standard free energy change (∆G°) for the following redox reaction at 25°C:2 Fe³⁺(aq) + 3 H₂(g) → 2 Fe(s) + 6 H⁺(aq)
asked
Feb 3
in
Chemical thermodynamics
by
AubreyWoore
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2.4k
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0
votes
1
answer
111
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Calculate the standard entropy change for the reaction of 2 moles of nitrogen gas reacting with 5 moles of oxygen gas to produce 2 moles of nitrogen monoxide gas at a constant pressure of 1 bar and 298 K. Given the standard molar entropy of nitrogen gas, oxygen gas, and nitrogen monoxide gas to be 191.6 J K-1 mol-1, 205.0 J K-1 mol-1, and 210.6 J K-1 mol-1, respectively.
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Feb 3
in
Chemical thermodynamics
by
JudithMackni
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2.3k
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0
votes
1
answer
60
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Calculate the standard entropy change for the reaction below at a temperature of 298 K:CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) The standard molar entropies are as follows: S(CH4) = 186.3 J K^-1 mol^-1S(O2) = 205.0 J K^-1 mol^-1S(CO2) = 213.7 J K^-1 mol^-1S(H2O) = 188.8 J K^-1 mol^-1
asked
Feb 3
in
Chemical thermodynamics
by
HenryCharles
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2.0k
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0
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1
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87
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Calculate the standard entropy change for the following reaction at 298 K:CH4(g) + 2O2(g) -> CO2(g) + 2H2O(l) Given the standard entropies of CH4(g), O2(g), CO2(g), and H2O(l) are 186.26 J/K/mol, 205.03 J/K/mol, 213.74 J/K/mol, and 69.95 J/K/mol respectively.
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Feb 3
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Chemical thermodynamics
by
EmerySynan65
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1.8k
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0
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1
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121
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Calculate the standard enthalpy of formation of water using Hess's law and the following data:2H2(g) + O2(g) -> 2H2O(g) ΔH°rxn = -484 kJ/molH2(g) + 1/2O2(g) -> H2O(l) ΔH°rxn = -286 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
MaximoVardon
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1.9k
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0
votes
1
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43
views
Calculate the standard enthalpy of formation of water if you know that the standard enthalpy of combustion of hydrogen is -286 kJ/mol and the standard enthalpy of combustion of oxygen is -394 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
ZellaSeamon3
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1.6k
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0
votes
1
answer
71
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Calculate the standard enthalpy of formation of propane (C3H8) given the following data:- Standard enthalpy of formation of CO2(g) = -393.5 kJ/mol- Standard enthalpy of formation of H2O(l) = -285.8 kJ/mol- Standard enthalpy of combustion of propane at constant pressure = -2220.1 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
NicholasTwm2
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2.0k
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+1
vote
1
answer
94
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Calculate the standard enthalpy of formation of potassium nitrate (KNO3) given the following information:- Heat of combustion of potassium is -468 kJ/mol- Heat of combustion of nitrogen is -940 kJ/mol- Heat of combustion of oxygen is -283.8 kJ/mol- Heat of formation of KNO3 is -383 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
MerissaGxv8
(
1.7k
points)
0
votes
1
answer
69
views
Calculate the standard enthalpy of formation of carbon dioxide given the following information: - Standard enthalpy of formation of graphite = 0 kJ/mol- Standard enthalpy of formation of oxygen gas = 0 kJ/mol- Enthalpy of combustion of graphite = -393.5 kJ/mol- Enthalpy of combustion of carbon monoxide = -283.0 kJ/mol- Enthalpy of combustion of hydrogen gas = -285.8 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
AnjaAbt20068
(
2.0k
points)
0
votes
1
answer
55
views
Calculate the standard enthalpy of formation of ammonia gas (NH3) using the following information:- Standard enthalpy of formation for nitrogen gas (N2) = 0 kJ/mol- Standard enthalpy of formation for hydrogen gas (H2) = 0 kJ/mol- Standard enthalpy of formation for ammonia gas (NH3) = -46 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
JulianaKane
(
2.2k
points)
0
votes
1
answer
63
views
Calculate the standard enthalpy of formation for propene (C3H6) given that the standard enthalpy of combustion of propene is -1411.1 kJ/mol and the standard enthalpy of formation of carbon dioxide (CO2) and water (H2O) are -393.5 kJ/mol and -285.8 kJ/mol respectively.
asked
Feb 3
in
Chemical thermodynamics
by
Vern5918460
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2.5k
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0
votes
1
answer
67
views
Calculate the standard enthalpy of formation for hydrogen peroxide (H2O2) at 298 K, given that the standard enthalpy change of formation for water (H2O) is -285.8 kJ/mol and the standard enthalpy change of formation for oxygen gas (O2) is 0 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
AddieFrayne
(
1.7k
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0
votes
1
answer
45
views
Calculate the standard enthalpy of formation for carbon dioxide (CO2) given the following information: ΔHf° of CO = -26.4 kJ/mol, ΔHf° of O2 = 0 kJ/mol, and ΔH°rxn for the combustion of carbon to form CO2 is -393.5 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
EmileR968610
(
2.0k
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0
votes
1
answer
80
views
Calculate the standard enthalpy of formation (ΔH°f) for butane (C4H10) given the following data:ΔH°f (kJ/mol)C(s) 0H2(g) 0C2H6(g) -84.7C3H8(g) -103.8Note: You may assume that butane undergoes complete combustion to form CO2(g) and H2O(l) and that the standard enthalpies of combustion for C4H10, CO2, and H2O are -2877.2, -393.5, and -285.8 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
KrystleFarth
(
1.7k
points)
0
votes
1
answer
74
views
Calculate the standard enthalpy change of the reaction between 100.0 mL of 0.100 M HCl(aq) and 100.0 mL of 0.100 M NaOH(aq) at 25°C, given that the specific heat capacity of the final solution is 4.18 J/g·°C and that the density of the final solution is 1.00 g/mL.
asked
Feb 3
in
Chemical thermodynamics
by
ImaSimmons79
(
2.3k
points)
0
votes
1
answer
72
views
Calculate the standard enthalpy change of the precipitation reaction between 50.0 mL of 0.100 M Pb(NO3)2 and excess 0.100 M NaCl solution at 25°C given that the reaction is Pb(NO3)2 (aq) + 2NaCl (aq) → PbCl2(s) + 2NaNO3 (aq) and the enthalpy of formation of NaNO3 (aq) and NaCl (aq) are -467.7 kJ/mol and -411.2 kJ/mol respectively.
asked
Feb 3
in
Chemical thermodynamics
by
SNBBernd7967
(
2.3k
points)
0
votes
1
answer
65
views
Calculate the standard enthalpy change of the formation reaction for carbon dioxide (CO2) given the standard enthalpies of formation for carbon monoxide (CO) and oxygen gas (O2) as -110.5 kJ/mol and -249.2 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
RobertoMundy
(
1.7k
points)
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