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Calculate the standard enthalpy change for the following reaction:2Fe(s) + 3/2O2(g) → Fe2O3(s)Given that the standard enthalpy of formation of Fe2O3(s) is -824 kJ/mol and the standard enthalpy of formation of Fe(s) and O2(g) are 0 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
KirbyLibby3
(
370
points)
0
votes
1
answer
37
views
Calculate the standard enthalpy change for the following reaction: [CoCl(NH3)5]2+ (aq) + 4H2O (l) → [Co(H2O)6]2+ (aq) + 2Cl- (aq) + 5NH3 (g)Given that the standard enthalpy of formation of [Co(H2O)6]2+ (aq) is -1518.5 kJ/mol, [CoCl(NH3)5]2+ (aq) is -426.9 kJ/mol, and the enthalpy of vaporization of water is 44.0 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
EmiliaOddo6
(
330
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy change for the following reaction: Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) given the following standard enthalpy of formation values: ΔHf°[Fe2O3(s)] = -824.2 kJ/mol ΔHf°[CO(g)] = -110.5 kJ/mol ΔHf°[Fe(s)] = 0 kJ/mol ΔHf°[CO2(g)] = -393.5 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
DessieMorrel
(
230
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy change for the following reaction: 2NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2H2O(l) Given the following information: - The standard enthalpy of formation of NaOH(aq) is -469.20 kJ/mol - The standard enthalpy of formation of H2SO4(aq) is -814.50 kJ/mol - The standard enthalpy of formation of Na2SO4(aq) is -1388.10 kJ/mol Note: Make sure to balance the equation and use Hess's Law if necessary.
asked
Feb 3
in
Chemical thermodynamics
by
Nora32F60079
(
310
points)
0
votes
1
answer
43
views
Calculate the standard enthalpy change for the following reaction: 2H2(g) + O2(g) → 2H2O(l)Given the standard enthalpies of formation for H2O (l), H2 (g) and O2 (g) are -285.8 kJ/mol, 0 kJ/mol and 0 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
JerriMacRory
(
590
points)
0
votes
1
answer
39
views
Calculate the standard enthalpy change for the following reaction: [Fe(H2O)6]2+(aq) + SO4 2-(aq) → [Fe(H2O)5 SO4]-(aq) + H2O(l) given that the standard enthalpies of formation of [Fe(H2O)6]2+, [Fe(H2O)5SO4]-, and H2O are -360 kJ/mol, -950 kJ/mol, and -286 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
AngeliaVande
(
430
points)
0
votes
1
answer
32
views
Calculate the standard enthalpy change for the following reaction, given the standard enthalpies of formation:2Fe (s) + 3Cl2 (g) → 2FeCl3 (s)ΔH°f(FeCl3) = -399.4 kJ/molΔH°f(Fe) = 0 kJ/molΔH°f(Cl2) = 0 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
QFFNeil45469
(
270
points)
0
votes
1
answer
26
views
Calculate the standard enthalpy change for the following reaction involving solids at 298 K:Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) Given the following standard enthalpies of formation in kJ/mol: Fe2O3(s) = -825.5 Fe(s) = 0CO2(g) = -393.5 CO(g) = -110.5
asked
Feb 3
in
Chemical thermodynamics
by
Chassidy39S
(
250
points)
0
votes
1
answer
39
views
Calculate the standard enthalpy change for the following reaction involving liquids at 298 K: C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)Given the standard enthalpies of formation of C2H5OH(l), CO2(g) and H2O(l) are −277.6 kJ/mol, −393.5 kJ/mol and −285.8 kJ/mol respectively.
asked
Feb 3
in
Chemical thermodynamics
by
FlynnFlorey3
(
410
points)
0
votes
1
answer
42
views
Calculate the standard enthalpy change for the following reaction at 298 K:Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
asked
Feb 3
in
Quantum Chemistry
by
AbrahamMcder
(
390
points)
0
votes
1
answer
36
views
Calculate the standard enthalpy change for the following reaction at 298 K: 2NaHCO3(s) + MgCl2(aq) → MgCO3(s) + 2NaCl(aq) + H2O(l)Given the following standard enthalpies of formation: ΔHf°(NaHCO3) = -950.7 kJ/molΔHf°(MgCl2) = -641.8 kJ/molΔHf°(MgCO3) = -1128.2 kJ/molΔHf°(NaCl) = -411.2 kJ/molΔHf°(H2O) = -285.8 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
EdwardPersse
(
230
points)
0
votes
1
answer
31
views
Calculate the standard enthalpy change for the following reaction at 298 K using the standard enthalpies of formation:2SO2(g) + O2(g) → 2SO3(g)
asked
Feb 3
in
Chemical thermodynamics
by
JameyBrinkle
(
410
points)
0
votes
1
answer
36
views
Calculate the standard enthalpy change for the following reaction at 25°C given the enthalpies of formation (in kJ/mol) of the compounds involved:CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)Hf(CaCO3) = -1206.9 kJ/molHf(CaCl2) = -795.8 kJ/molHf(CO2) = -393.5 kJ/molHf(H2O) = -285.8 kJ/molHf(HCl) = -92.31 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
BarbN430412
(
330
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy change for the following neutralization reaction where hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water (H2O).HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)Given the following tabulated standard enthalpies of formation values: ΔHf°(HCl) = -167 kJ/mol, ΔHf°(NaOH) = -469 kJ/mol, ΔHf°(NaCl) = -411 kJ/mol, ΔHf°(H2O) = -286 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
LovieDunross
(
250
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy change for the following neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH):HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)Given: - The standard enthalpy of formation (ΔHf°) of NaCl(aq) is -407.3 kJ/mol.- The standard enthalpy of formation (ΔHf°) of H2O(l) is -285.8 kJ/mol.- The specific heat capacity (c) of the solution is 4.18 J/g°C.- The temperature change (ΔT) during the reaction is 15°C. - The mass (m) of the solution is 50.0 g. What is the standard enthalpy change (ΔH°) for the neutralization reaction between HCl and NaOH?
asked
Feb 3
in
Chemical thermodynamics
by
LasonyaMarro
(
430
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy change for the following chemical reaction involving solutions:2HNO3(aq) + Ba(OH)2(aq) → Ba(NO3)2(aq) + 2H2O(l)Given the following information:ΔHf° [HNO3(aq)] = -207.5 kJ/molΔHf° [Ba(OH)2(aq)] = -994.0 kJ/molΔHf° [Ba(NO3)2(aq)] = -537.5 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
YasminDuncan
(
550
points)
0
votes
1
answer
27
views
Calculate the standard enthalpy change for the dissolution reaction of 10.0 g of NaOH(s) in 100.0 g of water at 25°C, given that the heat absorbed by the solution is 9.14 kJ. (Molar mass of NaOH = 40.00 g/mol and specific heat capacity of water = 4.18 J/g·°C)
asked
Feb 3
in
Chemical thermodynamics
by
LonBaskett07
(
610
points)
0
votes
1
answer
28
views
Calculate the standard enthalpy change for the dissolution of 5g of sodium chloride in 100mL of water at 25°C, given that the molar enthalpy of dissolution of NaCl is -3.9 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
MeaganBertra
(
470
points)
0
votes
1
answer
30
views
Calculate the standard enthalpy change for the dissolution of 5.36 g of NaOH in 100.0 mL of water, given that the molar enthalpy of dissolution for NaOH is -44.5 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
AlexandraVic
(
270
points)
0
votes
1
answer
21
views
Calculate the standard enthalpy change for the dissolution of 5.00 g of solid sodium hydroxide (NaOH) in water, given that the molar enthalpy of dissolution of NaOH is -44.51 kJ/mol. Assume that the specific heat capacity and density of the solution are the same as pure water and that no heat is lost to the surroundings during the dissolution process.
asked
Feb 3
in
Chemical thermodynamics
by
GayeT1039795
(
210
points)
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