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Calculate the standard enthalpy change (ΔH°) for the following reaction involving the coordination compound [Fe(H2O)6]2+:[Fe(H2O)6]2+(aq) + 2Cl-(aq) → [FeCl2(H2O)4](aq) + 2H2O(l) Given: ΔH°f [FeCl2(H2O)4](aq) = -334 kJ/mol ΔH°f [Fe(H2O)6]2+(aq) = -393 kJ/mol ΔH°f H2O(l) = -286 kJ/mol Note: The superscript ° denotes standard conditions (i.e. 1 atm and 25°C) and the superscript f denotes standard enthalpy of formation.
asked
Feb 3
in
Chemical thermodynamics
by
Phoebe93219
(
530
points)
0
votes
1
answer
36
views
Calculate the standard enthalpy change (ΔH°) for the following reaction at 298 K:2SO₂(g) + O₂(g) → 2SO₃(g)given the following standard enthalpy of formation values:ΔH°f (SO₂(g)) = -296.8 kJ/molΔH°f (O₂(g)) = 0 kJ/molΔH°f (SO₃(g)) = -395.7 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
RodI72248288
(
260
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy change (ΔH°) for the following reaction at 25°C, given that the enthalpies of formation for the reactants and products are:HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)ΔH°f[HCl (aq)] = -92.31 kJ/molΔH°f[NaOH (aq)] = -469.49 kJ/molΔH°f[NaCl (aq)] = -407.29 kJ/molΔH°f[H2O (l)] = -285.83 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
ClariceMcGhe
(
470
points)
0
votes
1
answer
31
views
Calculate the standard enthalpy change (ΔH°) for the combustion reaction of ethanol (C2H5OH) if the heat evolved is 1367.6 kJ and the molar mass of ethanol is 46.07 g/mol.
asked
Feb 3
in
Chemical thermodynamics
by
WendellGosho
(
330
points)
0
votes
1
answer
37
views
Calculate the standard enthalpy change (ΔH°) and standard entropy change (ΔS°) for the decomposition reaction of calcium carbonate (CaCO3) at 298 K:CaCO3(s) → CaO(s) + CO2(g)
asked
Feb 3
in
Inorganic Chemistry
by
MayraBeckwit
(
470
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy change (in kJ/mol) for the reaction of hydrochloric acid (HCl) and sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water (H2O), given the following balanced chemical equation:HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)Assume the reaction takes place under standard conditions (298 K and 1 atm pressure) and that all solutions have a concentration of 1.0 M. The standard enthalpies of formation for HCl (aq), NaOH (aq), NaCl (aq), and H2O (l) are -92.31 kJ/mol, -469.14 kJ/mol, -407.76 kJ/mol, and -285.83 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
MckinleyAlba
(
490
points)
0
votes
1
answer
35
views
Calculate the standard enthalpy change (in kJ/mol) for the neutralization reaction of hydrochloric acid (HCl) and sodium hydroxide (NaOH) using the following information: HCl (aq) + NaOH (aq) → NaCl (aq) + H2O(l)ΔHf° (kJ/mol): HCl (aq) = -167.2 NaOH (aq) = -469.2 NaCl (aq) = -407.3 H2O(l) = -285.8
asked
Feb 3
in
Chemical thermodynamics
by
EarleneSumme
(
290
points)
0
votes
1
answer
44
views
Calculate the standard enthalpy change (in kJ/mol) for the following reaction involving solutions: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)Given the following enthalpy values:NaOH(aq): -469.2 kJ/mol HCl(aq): -167.2 kJ/mol NaCl(aq): -411.2 kJ/mol H2O(l): -285.8 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
CaitlinMedra
(
370
points)
0
votes
1
answer
38
views
Calculate the standard enthalpy change (in kJ/mol) for the following chemical reaction at 298 K:2SO2(g) + O2(g) → 2SO3(g)Given the standard enthalpies of formation (∆Hf°) at 298 K for SO2(g), O2(g), and SO3(g) are -296.8 kJ/mol, 0 kJ/mol, and -396.0 kJ/mol, respectively.
asked
Feb 3
in
Physical Chemistry
by
RuthRoche423
(
330
points)
0
votes
1
answer
38
views
Calculate the standard enthalpy change (in kJ/mol) for the dissolution of 3.50 g of potassium hydroxide (KOH) in 250.0 mL of water at 25°C, given that the molar heat of solution of KOH is -57.61 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
TrishaSutton
(
270
points)
0
votes
1
answer
27
views
Calculate the standard enthalpy change (∆H°) of combustion for methane gas (CH4) given that the heat of formation (∆Hf°) for methane is -74.87 kJ/mol and the heat of formation (∆Hf°) for carbon dioxide (CO2) is -393.51 kJ/mol, and the heat of formation (∆Hf°) for water (H2O) is -285.83 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
LucieFrank2
(
350
points)
0
votes
1
answer
26
views
Calculate the standard enthalpy change (∆H°) for the vaporization of 10 grams of water at 100°C, given that the molar heat of vaporization of water is 40.7 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
MalissaFuchs
(
320
points)
0
votes
1
answer
43
views
Calculate the standard enthalpy change (∆H°) for the reaction: NaOH(aq) + HCl(aq) -> NaCl(aq) + H2O(l) given the following information: - The enthalpy change of neutralization of HCl(aq) with NaOH(aq) is -55.9 kJ/mol. - The enthalpy of formation of NaCl(s) is -411.2 kJ/mol.- The enthalpy of vaporization of water (H2O) is 40.7 kJ/mol.Assume that the specific heat capacity of the water is 4.18 J/g K and the density of the solution is 1 g/mL.
asked
Feb 3
in
Chemical thermodynamics
by
StevieGottli
(
410
points)
0
votes
1
answer
35
views
Calculate the standard enthalpy change (∆H°) for the reaction: 2HCl(aq) + Na2CO3(aq) → CO2(g) + H2O(l) + 2NaCl(aq) given that the standard enthalpy of formation (∆H°f) for NaCl(aq), H2O(l) and CO2(g) are -407.3 kJ/mol, -285.8 kJ/mol and -393.5 kJ/mol respectively.
asked
Feb 3
in
Chemical thermodynamics
by
TrentAdam35
(
490
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy change (∆H°) for the reaction: 2NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l)Given the following bond dissociation energies (in kJ/mol):N≡N = 941, N-H = 391, O=O = 495, O-H = 464, N-O = 201, H-O-H = 464, N-H + O=O = 632, N=O = 607, and H-N≡N = 945.
asked
Feb 3
in
Quantum Chemistry
by
TinaGottshal
(
530
points)
0
votes
1
answer
35
views
Calculate the standard enthalpy change (∆H°) for the reaction that involves the formation of complex [Fe(H2O)6]Cl3 from its constituent ions, given the following information: Fe3+(aq) + 6H2O(l) ⇌ [Fe(H2O)6]3+ ∆Hf° = +123 kJ/mol Cl-(aq) ∆Hf° = -167 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
ColeRubin252
(
470
points)
0
votes
1
answer
31
views
Calculate the standard enthalpy change (∆H°) for the reaction of the coordination compound [Co(NH3)6]Cl3 (aq) with NaOH (aq) to produce [Co(NH3)6](OH)3 (aq) and NaCl (aq). Given, the standard enthalpy of formation (∆H°f) for [Co(NH3)6]Cl3, [Co(NH3)6](OH)3 and NaCl are -784.8 kJ/mol, -1273.6 kJ/mol and -411.2 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
AlfredoHuber
(
350
points)
0
votes
1
answer
43
views
Calculate the standard enthalpy change (∆H°) for the reaction between 50.0 mL of 0.100 M hydrochloric acid (HCl) and 50.0 mL of 0.100 M sodium hydroxide (NaOH), given that the temperature change was -5.01°C and the specific heat capacity of the solution is 4.18 J/g°C. The balanced chemical equation for the reaction is:HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)Note: Assume the density of the solutions is 1.00 g/mL and that the specific heat capacity of the solutions is the same as that of water.
asked
Feb 3
in
Chemical thermodynamics
by
LawrenceJami
(
510
points)
0
votes
1
answer
43
views
Calculate the standard enthalpy change (∆H°) for the reaction between 25.0 mL of 0.100 M HCl and 25.0 mL of 0.100 M NaOH at 25°C. The density of each solution is 1.00 g/mL and the heat capacity of the solution is 4.18 J/g·°C. The reaction takes place in a calorimeter, and the temperature increase is measured to be 8.47°C.
asked
Feb 3
in
Chemical thermodynamics
by
AnnmarieNune
(
190
points)
0
votes
1
answer
27
views
Calculate the standard enthalpy change (∆H°) for the precipitation reaction between aqueous solutions of silver nitrate (AgNO3) and sodium chloride (NaCl) to form solid silver chloride (AgCl), given that 50.0 mL of 0.100 M AgNO3 and 50.0 mL of 0.100 M NaCl were combined in a calorimeter and the temperature change was recorded as -2.5°C.
asked
Feb 3
in
Chemical thermodynamics
by
CindyYamada9
(
390
points)
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