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votes
1
answer
41
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Calculate the standard enthalpy change for the dissolution of 10 g of NaOH in 100 mL of water at 25°C if the molar enthalpy of dissolution is -44.5 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
ThereseRosso
(
310
points)
0
votes
1
answer
43
views
Calculate the standard enthalpy change for the complete combustion of methane gas (CH4) at 25°C and 1 atm pressure, given that the standard enthalpy of formation for CH4 is -74.9 kJ/mol and the standard enthalpy of formation for water (H2O) is -285.8 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
BettinaChirn
(
290
points)
0
votes
1
answer
30
views
Calculate the standard enthalpy change for the complete combustion of methane gas (CH4(g)) at constant pressure, given the balanced equation: CH4(g) + 2O2(g) → CO2(g) + 2H2O(l). The standard enthalpies of formation of CO2(g), H2O(l), and CH4(g) are -393.5 kJ/mol, -285.8 kJ/mol, and -74.8 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
LachlanFrair
(
330
points)
0
votes
1
answer
31
views
Calculate the standard enthalpy change for the complete combustion of methane (CH4) at constant pressure and 298 K, given that the standard enthalpies of formation for CH4(g) and H2O(l) are -74.8 kJ/mol and -285.8 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
DebraAtkinso
(
230
points)
0
votes
1
answer
35
views
Calculate the standard enthalpy change for the complete combustion of 2 moles of methane gas under standard conditions, where all reactants and products are in their standard states. The balanced chemical equation for the combustion of methane is CH4(g) + 2O2(g) → CO2(g) + 2H2O(l), and the standard enthalpy of formation ΔH°f for methane, carbon dioxide, and water are -74.8 kJ/mol, -393.5 kJ/mol, and -285.8 kJ/mol, respectively.
asked
Feb 3
in
Chemical thermodynamics
by
CecilB463053
(
310
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy change for the combustion reaction of octane (C8H18) using the following balanced chemical equation:C8H18 + 12.5O2 →8CO2 + 9H2O Given the standard enthalpies of formation for CO2, H2O, and octane are -394 kJ/mol, -286 kJ/mol, and -249 kJ/mol respectively.
asked
Feb 3
in
Chemical thermodynamics
by
MelvinSalomo
(
490
points)
0
votes
1
answer
44
views
Calculate the standard enthalpy change for the combustion of methane gas using the following reaction: CH4(g) + 2O2(g) → CO2(g) + 2H2O(g). Given the standard enthalpy of formation values for methane, carbon dioxide, and water, calculate the heat released or absorbed during this reaction. Express your answer in kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
EmilieBobb0
(
350
points)
0
votes
1
answer
28
views
Calculate the standard enthalpy change for the combustion of methane gas at standard conditions, given the following balanced chemical equation:CH4(g) + 2O2(g) -> CO2(g) + 2H2O(l)Note: Standard conditions refer to a temperature of 25°C and a pressure of 1 atm.
asked
Feb 3
in
Chemical thermodynamics
by
GerardMaes99
(
410
points)
0
votes
1
answer
38
views
Calculate the standard enthalpy change for the combustion of methane gas (CH4) given the balanced chemical equation:CH4(g) + 2O2(g) -> CO2(g) + 2H2O(l)The relevant standard enthalpies of formation are:ΔHf°[CH4(g)] = -74.87 kJ/molΔHf°[CO2(g)] = -393.5 kJ/molΔHf°[H2O(l)] = -285.8 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
EliBrinkman
(
370
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy change for the combustion of methane (CH4) at constant pressure, given that the standard enthalpies of formation are -74.87 kJ/mol for methane and -393.51 kJ/mol for carbon dioxide (CO2), and 2H2(g) + O2(g) → 2H2O(l) has a standard enthalpy change of -571.66 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
KathrinPenne
(
350
points)
0
votes
1
answer
16
views
Calculate the standard enthalpy change for the combustion of ethene gas (C2H4(g)) to form carbon dioxide gas (CO2(g)) and water vapor (H2O(g)), given the following thermochemical equations: C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(g) ΔH°=-1411 kJ/mol2H2(g) + O2(g) → 2H2O(g) ΔH°=-484 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
OpheliaTuggl
(
190
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy change for the combustion of ethane (C2H6) given the balanced chemical equation:C2H6(g) + 3.5 O2(g) → 2CO2(g) + 3H2O(l)Assume all reactants and products are in standard states and use the following standard enthalpy of formation values:ΔHf°(C2H6) = -84.7 kJ/molΔHf°(CO2) = -393.5 kJ/molΔHf°(H2O) = -285.8 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
RedaDoy9962
(
310
points)
0
votes
1
answer
39
views
Calculate the standard enthalpy change for the combustion of ethane (C2H6) gas to form carbon dioxide (CO2) gas and water (H2O) vapor at 298 K and 1 atm. The balanced chemical equation for the reaction is: C2H6(g) + 3.5 O2(g) → 2 CO2(g) + 3H2O(g) Given that the standard enthalpy of formation for C2H6(g) is -84.68 kJ/mol, CO2(g) is -393.51 kJ/mol, and H2O(g) is -241.82 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
JennaFairfax
(
470
points)
0
votes
1
answer
30
views
Calculate the standard enthalpy change for the combustion of 1 mole of propane gas (C3H8) at standard conditions using the following balanced chemical equation: C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(l)Given the standard enthalpy of formation values at 298K for C3H8(g), CO2(g), and H2O(l) as -103.8, -393.5, and -285.8 kJ/mol respectively, calculate the standard enthalpy change for the combustion reaction.
asked
Feb 3
in
Chemical thermodynamics
by
Margot259311
(
930
points)
0
votes
1
answer
30
views
Calculate the standard enthalpy change for the combustion of 1 mole of methane gas (CH4) under standard conditions given the following balanced chemical equation:CH4(g) + 2O2(g)→CO2(g) + 2H2O(g)(Standard conditions: temperature of 298K and pressure of 1 bar)
asked
Feb 3
in
Chemical thermodynamics
by
MiriamOtis62
(
690
points)
0
votes
1
answer
26
views
Calculate the standard enthalpy change and the standard entropy change for the reaction: 2HCl(g) + Mg(s) → MgCl2(s) + H2(g) Given the following standard enthalpy of formation values: - HCl(g) = -92.31 kJ/mol - MgCl2(s) = -641.8 kJ/mol - H2(g) = 0 kJ/mol - Mg(s) = 0 kJ/mol Also given the following standard molar entropy values:- HCl(g) = 186.9 J/Kmol - MgCl2(s) = 138.53 J/Kmol - H2(g) = 130.7 J/Kmol - Mg(s) = 32.85 J/Kmol
asked
Feb 3
in
Inorganic Chemistry
by
KeeleyGame0
(
290
points)
0
votes
1
answer
42
views
Calculate the standard enthalpy change and entropy change for the reaction: 2Fe(s) + 3/2O2(g) -> Fe2O3(s) Given the standard enthalpies of formation of Fe(s), O2(g), and Fe2O3(s) are -0.44 kJ/mol, 0 kJ/mol, and -826 kJ/mol, respectively. Also, the standard molar entropy of Fe2O3(s) is 87.4 J/(mol K).
asked
Feb 3
in
Inorganic Chemistry
by
MitchNina52
(
290
points)
0
votes
1
answer
23
views
Calculate the standard enthalpy change (ΔH°), standard entropy change (ΔS°) and standard Gibbs free energy change (ΔG°) of the reaction:2A(g) + 3B(g) → C(g) + 2D(g)given thatΔH°f[A(g)] = 200 kJ mol^-1Δ H°f [B(g)] = 100 kJ mol^-1Δ H°f [C(g)] = 400 kJ mol^-1Δ H°f [D(g)] = 0 kJ mol^-1ΔH°= -400 kJ mol^-1Temperature (T) = 298 KThe student needs to use their knowledge in quantum chemistry and thermodynamics to calculate the thermodynamic properties of the given reaction.
asked
Feb 3
in
Quantum Chemistry
by
Cathern38144
(
570
points)
0
votes
1
answer
38
views
Calculate the standard enthalpy change (ΔH°) for the reduction of iron(III) oxide (Fe2O3) to iron (Fe) given the following balanced chemical equation:2Fe2O3(s) + 3C(s) → 4Fe(s) + 3CO2(g)The enthalpy of formation for Fe2O3(s) is -824.2 kJ/mol and the enthalpy of formation for CO2(g) is -393.5 kJ/mol. All other substances are in their standard state.
asked
Feb 3
in
ThermoChemistry
by
HughLarge668
(
550
points)
0
votes
1
answer
46
views
Calculate the standard enthalpy change (ΔH°) for the reaction:2H2(g) + O2(g) → 2H2O(g)given the following bond energies:H-H = 436 kJ/mol, O=O = 498 kJ/mol, H-O = 463 kJ/mol
asked
Feb 3
in
Quantum Chemistry
by
ErmelindaHur
(
510
points)
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