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answer
20
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Calculate the standard enthalpy change for the phase transition of solid copper to liquid copper given the following data: - the melting point of copper is 1,085°C - the molar heat of fusion of copper is 13.1 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
ShelaSleeman
(
390
points)
0
votes
1
answer
29
views
Calculate the standard enthalpy change for the phase transition of ice to water at 298 K, given that the heat of fusion of ice is 6.01 kJ/mol and the molar heat capacity of ice and water are 37.0 J/(mol*K) and 75.3 J/(mol*K), respectively.
asked
Feb 3
in
Chemical thermodynamics
by
SimaMacBain4
(
430
points)
0
votes
1
answer
30
views
Calculate the standard enthalpy change for the neutralization reaction of hydrochloric acid (HCl) with sodium hydroxide (NaOH) when 50.0 mL of 1.0 M HCl reacts with 50.0 mL of 1.0 M NaOH in a constant pressure calorimeter. Assume the density of the final solution is the same as that of pure water (1 g/mL) and that the specific heat capacity of the final solution is 4.18 J/g K.
asked
Feb 3
in
Chemical thermodynamics
by
AidaMays139
(
330
points)
0
votes
1
answer
7
views
Calculate the standard enthalpy change for the neutralization reaction between hydrochloric acid and sodium hydroxide, given the balanced chemical equation: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) and the enthalpy change of formation values: ∆Hf°(NaCl(aq)) = -407.3 kJ/mol ∆Hf°(H2O(l)) = -285.83 kJ/mol ∆Hf°(HCl(aq)) = -167.2 kJ/mol ∆Hf°(NaOH(aq)) = -469.11 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
Hilda98N352
(
250
points)
0
votes
1
answer
31
views
Calculate the standard enthalpy change for the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH), given the balanced chemical equation: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l). The enthalpies of formation for NaCl(aq) and H2O(l) are -407.3 kJ/mol and -285.8 kJ/mol, respectively. The specific heat capacity of the solution is 4.18 J/(g*K), and the mass of the resulting solution is 100 g.
asked
Feb 3
in
Chemical thermodynamics
by
IsisHampton
(
610
points)
0
votes
1
answer
41
views
Calculate the standard enthalpy change for the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH), given the appropriate thermochemical equations and the following information:- Heat evolved during the reaction, Q = -58.35 kJ/mol- Moles of HCl used, n(HCl) = 0.05 mol- Concentration of NaOH solution, c(NaOH) = 2 M- Volume of NaOH solution used, V(NaOH) = 25.0 mL (assuming density of 1.00 g/mL)Show your calculations and include units in your final answer.
asked
Feb 3
in
Chemical thermodynamics
by
ElveraCook66
(
210
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy change for the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH), given that the reaction produces water and sodium chloride as products. The molar enthalpy of formation for water is -285.8 kJ/mol and for NaCl is -411.2 kJ/mol. The balanced chemical equation for the reaction is: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)
asked
Feb 3
in
Chemical thermodynamics
by
MaeBranson69
(
530
points)
0
votes
1
answer
29
views
Calculate the standard enthalpy change for the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) using the following information:- The standard enthalpy of formation for HCl is -92.31 kJ/mol - The standard enthalpy of formation for NaOH is -469.11 kJ/mol The balanced equation for the reaction is:HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)
asked
Feb 3
in
Chemical thermodynamics
by
RussellOdoms
(
270
points)
0
votes
1
answer
23
views
Calculate the standard enthalpy change for the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) in aqueous solutions. The balanced chemical equation for the reaction is as follows:HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) Given the enthalpy of formation for HCl(aq) is -167.2 kJ/mol, NaOH(aq) is -469.14 kJ/mol, NaCl(aq) is -407.3 kJ/mol, and H2O(l) is -285.83 kJ/mol. The reaction is carried out at standard temperature and pressure.
asked
Feb 3
in
Chemical thermodynamics
by
AngelineFlin
(
870
points)
0
votes
1
answer
28
views
Calculate the standard enthalpy change for the neutralization reaction between 50.0 mL of 0.100 M hydrochloric acid and 75.0 mL of 0.080 M sodium hydroxide. Given: the specific heat capacity of the solution is 4.18 J/g°C and the density of the solution is 1.00 g/mL. The balanced chemical equation for the reaction is HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l).
asked
Feb 3
in
Chemical thermodynamics
by
EllieFitzwat
(
530
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy change for the neutralization of hydrochloric acid (HCl) with sodium hydroxide (NaOH) in aqueous solution when 50.0 mL of 0.100 M HCl was used and 75.0 mL of 0.075 M NaOH was added. Assume that the specific heat capacity of the solution is 4.18 J/g·K and the density of the solution is 1.00 g/mL.
asked
Feb 3
in
Chemical thermodynamics
by
ClaudiaChamb
(
310
points)
0
votes
1
answer
24
views
Calculate the standard enthalpy change for the neutralization of HCl with NaOH, given that the heat of formation of water is -285.8 kJ/mol, the heat of formation of NaCl is -411.1 kJ/mol, and the initial concentrations of HCl and NaOH are 1.0 M.
asked
Feb 3
in
Chemical thermodynamics
by
OtiliaTemple
(
510
points)
0
votes
1
answer
26
views
Calculate the standard enthalpy change for the neutralization of 50.0 mL of 0.100 M hydrochloric acid with 50.0 mL of 0.100 M sodium hydroxide, assuming that the specific heat capacity of the resulting solution is 4.18 J/g °C and the density of the solution is 1.00 g/mL.
asked
Feb 3
in
Chemical thermodynamics
by
PhilomenaCor
(
510
points)
0
votes
1
answer
27
views
Calculate the standard enthalpy change for the neutralization of 50 mL of 0.1 M hydrochloric acid with 50 mL of 0.1 M sodium hydroxide at a constant temperature of 25°C, given that the specific heat capacity of the resulting solution is 4.18 J/g°C and its density is 1 g/mL.
asked
Feb 3
in
Chemical thermodynamics
by
Georgetta69W
(
450
points)
0
votes
1
answer
37
views
Calculate the standard enthalpy change for the neutralization of 50 mL of 0.1 M hydrochloric acid with 50 mL of 0.1 M sodium hydroxide at a constant pressure and a temperature of 25°C. The balanced equation for the reaction is: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)
asked
Feb 3
in
Chemical thermodynamics
by
PhillippRome
(
190
points)
0
votes
1
answer
26
views
Calculate the standard enthalpy change for the neutralization of 25.0 mL of 1.0 M hydrochloric acid (HCl) with 25.0 mL of 1.0 M sodium hydroxide (NaOH) solution at 25°C, given that the specific heat capacity of the solutions is 4.18 J/g°C, and the density of the solutions is 1.00 g/mL.
asked
Feb 3
in
Chemical thermodynamics
by
Wyatt28H007
(
390
points)
0
votes
1
answer
38
views
Calculate the standard enthalpy change for the neutralization of 25 mL of 0.10 M hydrochloric acid with 25 mL of 0.10 M sodium hydroxide. Assume the specific heat capacity of the solution to be 4.18 J/(g*K) and the density of the solution to be 1.00 g/mL. The temperature change observed during the reaction was 4.5°C.
asked
Feb 3
in
Chemical thermodynamics
by
GemmaDeamer7
(
290
points)
0
votes
1
answer
28
views
Calculate the standard enthalpy change for the melting of 10 grams of ice at -10°C to liquid water at 20°C, given the specific heat capacity of water is 4.18 J/g°C and the enthalpy of fusion of water is 6.01 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
VCSKarol0571
(
350
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy change for the liquid-to-gas phase transition of water at 100°C and atmospheric pressure, given that the enthalpy of vaporization of water is 40.7 kJ/mol.
asked
Feb 3
in
Chemical thermodynamics
by
BennieFll738
(
530
points)
0
votes
1
answer
50
views
Calculate the standard enthalpy change for the given reaction using the given data:2H2(g) + O2(g) --> 2H2O(l)Given:ΔHf°(H2O(l)) = -285.83 kJ/molΔHf°(O2(g)) = 0 kJ/molΔHf°(H2(g)) = 0 kJ/mol
asked
Feb 3
in
Chemical thermodynamics
by
JohannaGood
(
270
points)
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