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Recent questions in Chemistry
0
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1
answer
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Calculate the enthalpy change for the hydrolysis of sucrose given that 10.0 g of sucrose was completely hydrolyzed in excess water. The reaction takes place at 25°C and 1 atm pressure. The following reaction is involved: C12H22O11(s) + H2O(l) → 12C(s) + 11H2O(l) The enthalpy of formation of C12H22O11(s) is -2226.8 kJ/mol and the enthalpy of formation of H2O(l) is -285.8 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
DanielleCand
(
330
points)
0
votes
1
answer
45
views
Calculate the enthalpy change for the hydrolysis of 50 grams of sucrose (C12H22O11) when dissolved in 500 ml of water at 25°C. The molar mass of sucrose is 342.3 g/mol and the enthalpy change per mole of sucrose is -564.8 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
JeffereyHail
(
430
points)
0
votes
1
answer
55
views
Calculate the enthalpy change for the hydrolysis of 5.5 grams of sucrose (C12H22O11) using the standard enthalpy of formation values of the products and reactants. Assume the reaction takes place at constant pressure and temperature of 25°C.
asked
Jan 23
in
ThermoChemistry
by
JoshuaStamps
(
290
points)
0
votes
1
answer
45
views
Calculate the enthalpy change for the hydrolysis of 5 moles of methyl acetate using the given bond enthalpies: C-O (360 kJ/mol), C=O (740 kJ/mol), O-H (460 kJ/mol), and C-H (410 kJ/mol).
asked
Jan 23
in
ThermoChemistry
by
LanePeacock
(
410
points)
0
votes
1
answer
47
views
Calculate the enthalpy change for the hydrolysis of 2 moles of sucrose (C12H22O11) into glucose (C6H12O6) and fructose (C6H12O6), given the enthalpy change of hydrolysis for glucose and fructose are -2801 and -2802 kJ/mol respectively.
asked
Jan 23
in
ThermoChemistry
by
Zack25G18861
(
490
points)
0
votes
1
answer
49
views
Calculate the enthalpy change for the hydrolysis of 2 moles of sucrose (C12H22O11) into glucose (C6H12O6) and fructose (C6H12O6) given the following information:- Enthalpy of formation of glucose = -1273 kJ/mol- Enthalpy of formation of fructose = -1260 kJ/mol- Enthalpy of formation of sucrose = -2226 kJ/mol
asked
Jan 23
in
ThermoChemistry
by
Gregg1627959
(
890
points)
0
votes
1
answer
53
views
Calculate the enthalpy change for the hydrolysis of 2 moles of sucrose (C12H22O11) in aqueous solution given that the heat capacity of the solution is 4.18 J/g.K, the initial and final temperatures of the solution are 22.0°C and 28.0°C respectively. The molar mass of sucrose is 342.3 g/mol.
asked
Jan 23
in
ThermoChemistry
by
AugustinaLjy
(
470
points)
0
votes
1
answer
43
views
Calculate the enthalpy change for the hydrolysis of 2 moles of sucrose (C12H22O11) if it releases 5184 kJ/mol of energy.
asked
Jan 23
in
ThermoChemistry
by
JosephDelato
(
440
points)
0
votes
1
answer
32
views
Calculate the enthalpy change for the hydrolysis of 2 moles of sucrose (C12H22O11) given the standard enthalpies of formation of sucrose, glucose, and fructose are -2220 kJ/mol, -1274 kJ/mol, and -915 kJ/mol respectively.
asked
Jan 23
in
ThermoChemistry
by
JefferySerra
(
590
points)
0
votes
1
answer
41
views
Calculate the enthalpy change for the hydrolysis of 2 moles of sucrose (C12H22O11) given that the enthalpy change of hydrolysis for 1 mole of sucrose is -564 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
EzequielKrug
(
170
points)
0
votes
1
answer
43
views
Calculate the enthalpy change for the hydrolysis of 2 moles of magnesium bromide, MgBr2, in water, given that the standard enthalpy change of formation of magnesium oxide, MgO, is -601.6 kJ/mol and the standard enthalpy change of formation of hydrogen bromide, HBr, is -36.3 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
MargaretaBal
(
570
points)
0
votes
1
answer
49
views
Calculate the enthalpy change for the hydrolysis of 10 grams of sodium acetate (NaOH) at 25°C, given the following information:- The specific heat capacity of the solution is 4.18 J/(g·°C)- The initial temperature of the solution is 25°C- The final temperature of the solution after hydrolysis is 30°C- The heat evolved by the reaction is 677 J.
asked
Jan 23
in
ThermoChemistry
by
Woodrow18V43
(
430
points)
0
votes
1
answer
35
views
Calculate the enthalpy change for the hydrolysis of 0.1 moles of sucrose in water given the following information: - The enthalpy change of the reaction is -564 kJ/mol.- The molar mass of sucrose is 342.3 g/mol.- The reaction is exothermic.
asked
Jan 23
in
ThermoChemistry
by
EtsukoGunter
(
330
points)
0
votes
1
answer
55
views
Calculate the enthalpy change for the hydrolysis of 0.025 moles of ethyl acetate (C4H8O2) in the presence of excess water, given that the enthalpy of reaction is -56.0 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
OctaviaBarne
(
450
points)
0
votes
1
answer
56
views
Calculate the enthalpy change for the hydration of MgSO4 using the following data:MgSO4(s) → MgSO4(aq) ΔH1 = 44.5 kJ/molMgSO4(aq) + 7H2O(l) → MgSO4 • 7H2O(s) ΔH2 = -63.2 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
LeandroOxley
(
410
points)
0
votes
1
answer
39
views
Calculate the enthalpy change for the fusion of 50.0 g of ice at its melting point (0 °C). The molar enthalpy of fusion of water is 6.01 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
JoyMarkley53
(
710
points)
0
votes
1
answer
42
views
Calculate the enthalpy change for the following reaction:2H2O2(aq) → 2H2O(l) + O2(g)Using the following information:2H2O(l) + 105.2 kJ → 2H2(g) + O2(g)2H2(g) + O2(g) → 2H2O2(aq) + 484.4 kJ
asked
Jan 23
in
Chemical reactions
by
KristoferHol
(
830
points)
0
votes
1
answer
53
views
Calculate the enthalpy change for the following reaction, using Hess's Law:2H2S(g) + 3O2(g) → 2H2O(l) + 2SO2(g)Given the following enthalpy changes: 2H2(g) + O2(g) → 2H2O(l) ΔH1 = -484 kJ2SO2(g) + O2(g) → 2SO3(g) ΔH2 = -198 kJ2H2(g) + S(s) → H2S(g) ΔH3 = +25kJ
asked
Jan 23
in
Chemical reactions
by
ColinBatty1
(
450
points)
0
votes
1
answer
48
views
Calculate the enthalpy change for the following reaction using Hess's Law: 2SO3(g) → 2SO2(g) + O2(g)Given the following enthalpy changes:2SO3(g) + ΔH1 → 2SO2(g) + O2(g); ΔH1 = 198.2 kJ/molSO2(g) + 1/2O2(g) + ΔH2 → SO3(g); ΔH2 = -98.9 kJ/mol
asked
Jan 23
in
Chemical reactions
by
RodDeboer029
(
430
points)
0
votes
1
answer
36
views
Calculate the enthalpy change for the following reaction using Hess's Law calculations:2H2S(g) + 3O2(g) → 2H2O(l) + 2SO2(g)Given the following information:2H2(g) + O2(g) → 2H2O(l) ΔH1 = -484 kJ/mol2S(s) + 3O2(g) → 2SO3(g) ΔH2 = -791 kJ/mol2H2(g) + S(s) → 2H2S(g) ΔH3 = -36 kJ/mol
asked
Jan 23
in
ThermoChemistry
by
ElaneLavarac
(
590
points)
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