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Recent questions in Chemistry
0
votes
1
answer
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Calculate the heat of hydration of copper (II) sulfate pentahydrate given that 5.00 g of the hydrate was dissolved in 100.0 mL of water at 25°C, and the resulting solution temperature increased from 25°C to 30°C. The molar mass of copper (II) sulfate pentahydrate is 249.685 g/mol and the specific heat capacity of water is 4.184 J/g°C.
asked
Jan 23
in
ThermoChemistry
by
Breanna4436
(
550
points)
0
votes
1
answer
44
views
Calculate the heat of hydration of 1 mole of anhydrous copper(II) sulfate (CuSO4) when it is dissolved in water to form its hydrated form, CuSO4·5H2O. Given the following information:- Heat of solution of anhydrous CuSO4: -74.9 kJ/mol- Enthalpy change of hydration of CuSO4·5H2O: -245.1 kJ/mol
asked
Jan 23
in
ThermoChemistry
by
AnnettSheppa
(
510
points)
0
votes
1
answer
47
views
Calculate the heat of hydration for the reaction where 1 mole of anhydrous copper(II) sulfate reacts with water to form 5 moles of hydrated copper(II) sulfate, given that the enthalpy change for the reaction is -92.2 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
Beulah10W886
(
610
points)
0
votes
1
answer
39
views
Calculate the heat of hydration for the reaction where 1 mol of anhydrous copper sulfate combines with 5 mol of water to form 1 mol of hydrated copper sulfate given that the enthalpy change of the reaction is -65 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
PWOMazie102
(
650
points)
0
votes
1
answer
45
views
Calculate the heat of hydration for the reaction between anhydrous copper sulfate (CuSO4) and water (H2O), given that the mass of anhydrous copper sulfate used is 10 g and the temperature of the solution increases from 25°C to 35°C. The molar heat of hydration for copper sulfate pentahydrate (CuSO4.5H2O) is -90.1 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
Nydia78K370
(
530
points)
0
votes
1
answer
54
views
Calculate the heat of hydration for the reaction between 1 mol of anhydrous magnesium sulfate and enough water to produce 1 mol of hydrated magnesium sulfate, given that the enthalpy change of the reaction is -108 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
DerekMcQuay
(
550
points)
0
votes
1
answer
41
views
Calculate the heat of hydration for the dissolution of 5.00 grams of magnesium sulfate heptahydrate in 100.0 grams of water, given that the temperature rises from 25.0°C to 30.0°C. The molar mass of magnesium sulfate heptahydrate is 246.48 g/mol and the specific heat capacity of water is 4.18 J/g°C.
asked
Jan 23
in
ThermoChemistry
by
AlbertinaSpe
(
410
points)
0
votes
1
answer
50
views
Calculate the heat of hydration for the compound sodium sulfate (Na2SO4) given that 3 moles of water are released when 1 mole of the compound dissolves in water. The enthalpy of solution for sodium sulfate is -138 kJ/mol, and the enthalpy of hydration for water is -286 kJ/mol.
asked
Jan 23
in
ThermoChemistry
by
Dell11H9211
(
470
points)
0
votes
1
answer
49
views
Calculate the heat of hydration for magnesium ion when 0.5 moles of magnesium chloride is dissolved in 500 ml of water at 25°C. Given that the enthalpy change of solution for magnesium chloride is -641 kJ/mol and the specific heat capacity of water is 4.18 J/g°C.
asked
Jan 23
in
ThermoChemistry
by
MargheritaMa
(
530
points)
0
votes
1
answer
45
views
Calculate the heat of formation of water (H2O) given the following bond energies: H-H = 436 kJ/mol, O-H = 463 kJ/mol.
asked
Jan 23
in
Chemical bonding
by
April242096
(
680
points)
0
votes
1
answer
40
views
Calculate the heat of formation of Methane (CH4), given the following enthalpy changes:- Enthalpy change of combustion of methane = -890.4 kJ mol^-1- Enthalpy change of formation of water = -285.8 kJ mol^-1- Enthalpy change of formation of carbon dioxide = -393.5 kJ mol^-1
asked
Jan 23
in
Chemical bonding
by
JudyCottee50
(
630
points)
0
votes
1
answer
52
views
Calculate the heat of formation of methane (CH4) given the standard enthalpies of formation of carbon dioxide (CO2), water (H2O), and oxygen gas (O2).
asked
Jan 23
in
Chemical bonding
by
FlorineMmj33
(
610
points)
0
votes
1
answer
54
views
Calculate the heat of formation of methane (CH4) given the following values: - The standard enthalpy of combustion of methane is -890.3 kJ/mol- The bond energies are as follows: C-H = 413 kJ/mol and C-C = 348 kJ/mol.
asked
Jan 23
in
Chemical bonding
by
JamiNovotny2
(
590
points)
0
votes
1
answer
43
views
Calculate the heat of formation of methane (CH4) given the following thermochemical equations and standard heats of formation:2H2 (g) + O2 (g) → 2H2O (l) ΔH° = -572 kJ/molC (s) + O2 (g) → CO2 (g) ΔH° = -393.5 kJ/molNote: The standard heat of formation of CH4 is -74.8 kJ/mol.
asked
Jan 23
in
Chemical bonding
by
Genevieve973
(
350
points)
0
votes
1
answer
53
views
Calculate the heat of formation of methane (CH4) given the following bond energy values: C-H bond energy = 413 kJ/mol and C-C bond energy = 348 kJ/mol.
asked
Jan 23
in
Chemical bonding
by
CrystleHumph
(
530
points)
0
votes
1
answer
61
views
Calculate the heat of formation of methane (CH4) given the enthalpies of formation of H2(g) = 0 kJ/mol and CH3(g) = 120.6 kJ/mol.
asked
Jan 23
in
Chemical bonding
by
HassieCooch5
(
430
points)
0
votes
1
answer
41
views
Calculate the heat of formation of carbon dioxide gas (CO2) given the following bond energies: C=O bond energy is 799 kJ/mol and C-O bond energy is 358 kJ/mol.
asked
Jan 23
in
Chemical bonding
by
Margarita30G
(
490
points)
0
votes
1
answer
44
views
Calculate the heat of formation of carbon dioxide (CO2) using the following information: The heat of formation of carbon monoxide (CO) is -110.5 kJ/mol and the heat of formation of water (H2O) is -285.8 kJ/mol.
asked
Jan 23
in
Chemical bonding
by
JamesCutler4
(
250
points)
0
votes
1
answer
55
views
Calculate the heat of formation of carbon dioxide (CO2) given the following information: heat of formation of C(graphite) = 0 kJ/mol, heat of formation of O2(g) = 0 kJ/mol, and heat of combustion of graphite = -393.5 kJ/mol.
asked
Jan 23
in
Chemical bonding
by
KarryAutry49
(
410
points)
0
votes
1
answer
46
views
Calculate the heat of formation of a water molecule from its elements, hydrogen and oxygen gas, given that the standard enthalpy of formation of hydrogen gas is -285.8 kJ/mol and the standard enthalpy of formation of oxygen gas is 0 kJ/mol. Show all your work and explain what the resulting sign of the enthalpy of formation means in terms of the stability of the water molecule.
asked
Jan 23
in
Chemical bonding
by
FrancescaShe
(
530
points)
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