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Recent questions in Chemistry
0
votes
1
answer
30
views
Calculate the standard enthalpy of hydrolysis for the following reaction: AlCl3 + 3H2O → Al(OH)3 + 3HCl Given that the standard enthalpies of formation for AlCl3(-696.5 kJ/mol), Al(OH)3(-1277.1 kJ/mol), and HCl(-92.3 kJ/mol) are known.
asked
4 days
ago
in
ThermoChemistry
by
JulioDarrow7
(
750
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy of hydrolysis for Na2CO3 when 2.5 moles of water react with 1 mole of Na2CO3, given that the heat of reaction is -843.2 kJ/mol.
asked
4 days
ago
in
ThermoChemistry
by
MarilouMarco
(
450
points)
0
votes
1
answer
27
views
Calculate the standard enthalpy of formation, ΔH°f, of carbon dioxide (CO2) gas given the following thermochemical equations: C(s) + O2(g) → CO2(g) ΔH°rxn = -393.5 kJ/mol C(s) + O2(g) → CO(g) ΔH°rxn = -110.5 kJ/mol CO(g) + 1/2 O2(g) → CO2(g) ΔH°rxn = -283.0 kJ/mol Assume that all reactants and products are in their standard states.
asked
4 days
ago
in
ThermoChemistry
by
RodneyC3252
(
250
points)
0
votes
1
answer
31
views
Calculate the standard enthalpy of formation of water using Hess's law and the following data:2H2(g) + O2(g) -> 2H2O(g) ΔH°rxn = -484 kJ/molH2(g) + 1/2O2(g) -> H2O(l) ΔH°rxn = -286 kJ/mol
asked
4 days
ago
in
Chemical thermodynamics
by
Julio140610
(
510
points)
0
votes
1
answer
20
views
Calculate the standard enthalpy of formation of water if you know that the standard enthalpy of combustion of hydrogen is -286 kJ/mol and the standard enthalpy of combustion of oxygen is -394 kJ/mol.
asked
4 days
ago
in
Chemical thermodynamics
by
BillyEdge555
(
410
points)
0
votes
1
answer
19
views
Calculate the standard enthalpy of formation of water (H2O) given the following information:- The standard enthalpy of formation of hydrogen gas (H2) is 0 kJ/mol- The standard enthalpy of formation of oxygen gas (O2) is 0 kJ/mol- The standard enthalpy of combustion of hydrogen gas is -286 kJ/mol- The standard enthalpy of combustion of carbon (C) is -394 kJ/mol- The standard enthalpy of combustion of methane gas (CH4) is -890 kJ/mol
asked
4 days
ago
in
ThermoChemistry
by
Bradley53M38
(
490
points)
0
votes
1
answer
19
views
Calculate the standard enthalpy of formation of water (H2O) given the following information: ΔHf° of H2(g) = 0 kJ/molΔHf° of O2(g) = 0 kJ/molΔHf° of H2O2(l) = -188.2 kJ/mol
asked
4 days
ago
in
ThermoChemistry
by
RBFSuzette64
(
570
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy of formation of propane (C3H8) given the following data:- Standard enthalpy of formation of CO2(g) = -393.5 kJ/mol- Standard enthalpy of formation of H2O(l) = -285.8 kJ/mol- Standard enthalpy of combustion of propane at constant pressure = -2220.1 kJ/mol
asked
4 days
ago
in
Chemical thermodynamics
by
JessieStraub
(
330
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy of formation of potassium nitrate (KNO3) given the following information:- Heat of combustion of potassium is -468 kJ/mol- Heat of combustion of nitrogen is -940 kJ/mol- Heat of combustion of oxygen is -283.8 kJ/mol- Heat of formation of KNO3 is -383 kJ/mol.
asked
4 days
ago
in
Chemical thermodynamics
by
Ricardo42K0
(
430
points)
0
votes
1
answer
34
views
Calculate the standard enthalpy of formation of methanol, CH3OH (l), given that the standard enthalpy of combustion of methanol is -726.4 kJ/mol and the standard enthalpy of formation of carbon dioxide and water are -393.5 kJ/mol and -285.8 kJ/mol, respectively.
asked
4 days
ago
in
ThermoChemistry
by
RichGillilan
(
650
points)
0
votes
1
answer
33
views
Calculate the standard enthalpy of formation of methane gas (CH4) given the standard enthalpies of formation for carbon dioxide (CO2) (-393.5 kJ/mol) and water vapor (H2O) (-241.8 kJ/mol).
asked
4 days
ago
in
ThermoChemistry
by
ErnestinaB30
(
410
points)
0
votes
1
answer
41
views
Calculate the standard enthalpy of formation of methane gas (CH4) given the following data:- ∆H°combustion of methane = -890.36 kJ/mol - ∆H°formation of H2O (l) = -285.8 kJ/mol - ∆H°formation of CO2 (g) = -393.5 kJ/mol
asked
4 days
ago
in
ThermoChemistry
by
ChasLutwyche
(
470
points)
0
votes
1
answer
47
views
Calculate the standard enthalpy of formation of methane (CH4) given the following enthalpy data: C(graphite) + 2H2(g) → CH4(g) ΔH° = -74.8 kJ/mol ΔH°f[C(graphite)] = 0 kJ/molΔH°f[H2(g)] = 0 kJ/mol (Hint: Use Hess's Law and the fact that the standard enthalpy of formation of an element in its most stable state is zero.)
asked
4 days
ago
in
ThermoChemistry
by
DamianPelloe
(
610
points)
0
votes
1
answer
27
views
Calculate the standard enthalpy of formation of methane (CH4) given that the standard enthalpies of formation for CO2 and H2O are -393.5 kJ/mol and -285.8 kJ/mol, respectively.
asked
4 days
ago
in
ThermoChemistry
by
Woodrow18V43
(
430
points)
0
votes
1
answer
50
views
Calculate the standard enthalpy of formation of hydrogen fluoride (HF) given the following reactions and enthalpy change values:2H2(g) + O2(g) → 2H2O(g) ΔH° = -484 kJH2(g) + Cl2(g) → 2HCl(g) ΔH° = -184 kJ1/2 F2(g) + H2(g) → HF(g) ΔH° = -273 kJ.
asked
4 days
ago
in
ThermoChemistry
by
MadelineColl
(
770
points)
0
votes
1
answer
42
views
Calculate the standard enthalpy of formation of glucose (C6H12O6) given that the standard enthalpies of combustion for glucose, carbon, and hydrogen are -2803.6 kJ/mol, -393.5 kJ/mol, and -285.8 kJ/mol, respectively.
asked
4 days
ago
in
ThermoChemistry
by
Hilario7169
(
490
points)
0
votes
1
answer
28
views
Calculate the standard enthalpy of formation of ethane (C2H6) given the following bond energies (in kJ/mol):C-C: 347C-H: 413 Note: The equation for the formation of ethane is:C(graphite) + 3H2(g) -> C2H6(g)
asked
4 days
ago
in
ThermoChemistry
by
SkyeVillasen
(
610
points)
0
votes
1
answer
26
views
Calculate the standard enthalpy of formation of carbon dioxide given the following information: - Standard enthalpy of formation of graphite = 0 kJ/mol- Standard enthalpy of formation of oxygen gas = 0 kJ/mol- Enthalpy of combustion of graphite = -393.5 kJ/mol- Enthalpy of combustion of carbon monoxide = -283.0 kJ/mol- Enthalpy of combustion of hydrogen gas = -285.8 kJ/mol
asked
4 days
ago
in
Chemical thermodynamics
by
CarmaDurden
(
430
points)
0
votes
1
answer
28
views
Calculate the standard enthalpy of formation of carbon dioxide gas (CO2) given the following information: C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ/mol H2(g) + 1/2O2(g) → H2O(l) ΔH = -285.8 kJ/mol 2C(s) + 2H2(g) + 5/2O2(g) → 2CO2(g) + 2H2O(l) ΔH = -890.4 kJ/mol
asked
4 days
ago
in
ThermoChemistry
by
KraigPetheri
(
510
points)
0
votes
1
answer
23
views
Calculate the standard enthalpy of formation of carbon dioxide from its elements under standard conditions given the following information:- The standard enthalpy of combustion of carbon to CO2 is -393.5 kJ/mol- The standard enthalpy of combustion of hydrogen to H2O is -285.8 kJ/mol- The standard enthalpy of formation of water is -241.8 kJ/mol.Note: The standard enthalpy of formation of an element in its standard state is zero.
asked
4 days
ago
in
ThermoChemistry
by
DaisyZ884821
(
410
points)
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