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Calculate the standard electrode potential for the reaction Ag+ (aq) + Cu (s) → Ag (s) + Cu2+ (aq) given that the standard electrode potentials for Ag+ (aq) + e- → Ag (s) and Cu2+ (aq) + 2e- → Cu (s) are 0.80 V and 0.34 V respectively.

asked Feb 3 in Chemical thermodynamics by MandyPino165 (370 points)

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Calculate the overpotential for the reduction reaction of Ag+ to Ag on a silver electrode at 25°C with a current density of 0.5 A/cm2. The standard reduction potential of Ag+ to Ag is 0.799 V vs. the standard hydrogen electrode. The activation energy for this reaction is 65.0 kJ/mol, the transfer coefficient is 0.4 and the reaction order is 1.5.

asked Feb 3 in ElectroChemistry by RacheleChewi (390 points)

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Calculate the standard electrode potential for the following redox reaction at 298K:Fe3+(aq) + e- → Fe2+(aq) Given the E°(Fe3+/Fe2+) = +0.77V.

asked Feb 3 in Chemical thermodynamics by JerrellGoodi (630 points)

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How will changing the pH affect the formation of a complex ion between Fe³⁺ and CN⁻ in a solution containing both species at equilibrium? Provide a theoretical explanation supported by relevant chemical equations and calculations.

asked Feb 3 in Chemical equilibrium by SallyConlan1 (430 points)

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Calculate the standard enthalpy change for the sublimation of 5 moles of solid iodine (I2) given the following data:- Enthalpy of fusion of iodine = 15.52 kJ/mol- Enthalpy of vaporization of iodine = 41.57 kJ/mol

asked Feb 3 in Chemical thermodynamics by EmmaLeist635 (170 points)

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Calculate the standard enthalpy change (∆H°) of combustion for methane gas (CH4) given that the heat of formation (∆Hf°) for methane is -74.87 kJ/mol and the heat of formation (∆Hf°) for carbon dioxide (CO2) is -393.51 kJ/mol, and the heat of formation (∆Hf°) for water (H2O) is -285.83 kJ/mol.

asked Feb 3 in Chemical thermodynamics by ErvinNeill87 (450 points)

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Calculate the standard enthalpy change (∆H°) for the vaporization of 10 grams of water at 100°C, given that the molar heat of vaporization of water is 40.7 kJ/mol.

asked Feb 3 in Chemical thermodynamics by JensBonds677 (430 points)

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Calculate the standard enthalpy change and the standard entropy change for the reaction: 2HCl(g) + Mg(s) → MgCl2(s) + H2(g) Given the following standard enthalpy of formation values: - HCl(g) = -92.31 kJ/mol - MgCl2(s) = -641.8 kJ/mol - H2(g) = 0 kJ/mol - Mg(s) = 0 kJ/mol Also given the following standard molar entropy values:- HCl(g) = 186.9 J/Kmol - MgCl2(s) = 138.53 J/Kmol - H2(g) = 130.7 J/Kmol - Mg(s) = 32.85 J/Kmol

asked Feb 3 in Inorganic Chemistry by AlvinPayne11 (330 points)

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What is the effect of changing the concentration of reactants on the rate of reaction and the corresponding safety hazards in a given chemical reaction?

asked Feb 3 in Chemical kinetics by DelilaPike1 (410 points)

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Calculate the standard enthalpy of formation for carbon dioxide (CO2) given the following information: ΔHf° of CO = -26.4 kJ/mol, ΔHf° of O2 = 0 kJ/mol, and ΔH°rxn for the combustion of carbon to form CO2 is -393.5 kJ/mol.

asked Feb 3 in Chemical thermodynamics by CorineHumble (330 points)

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Calculate the standard enthalpy change for the formation of methane (CH4) given the following equations:C(s) + O2(g) ⟶ CO2(g); ΔH = -393.5 kJ/mol2H2(g) + O2(g) ⟶ 2H2O(l); ΔH = -571.6 kJ/mol

asked Feb 3 in Chemical thermodynamics by EstebanKenne (210 points)

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How does changing the concentration of reactants affect the reaction rate and determine the order of the reaction for the given chemical reaction?

asked Feb 3 in Chemical kinetics by BernadetteFi (390 points)

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Calculate the standard enthalpy change of the following chemical reaction at 298 K given the following bond energies: 2H2(g) + O2(g) --> 2H2O(l) Bond energies: H-H: 432 kJ/mol O=O: 498 kJ/mol O-H: 464 kJ/mol

asked Feb 3 in Physical Chemistry by VivienBeauch (490 points)

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Calculate the standard enthalpy change for the following reaction involving solids at 298 K:Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) Given the following standard enthalpies of formation in kJ/mol: Fe2O3(s) = -825.5 Fe(s) = 0CO2(g) = -393.5 CO(g) = -110.5

asked Feb 3 in Chemical thermodynamics by Chassidy39S (250 points)

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How does changing the concentration of reactants affect the rate of a chemical reaction, and can this relationship be modeled with a mathematical equation?

asked Feb 3 in Chemical kinetics by AllanKetchum (410 points)

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Calculate the pH of a 0.2 M solution of acetic acid (CH3COOH) if the acid dissociation constant (Ka) of acetic acid is 1.8 × 10^-5.

asked Feb 3 in Chemical reactions by LeomaDnl617 (370 points)

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Calculate the standard enthalpy change for the reaction of [Co(H2O)6]2+(aq) with 2 Cl-(aq) to form [CoCl4]2-(aq) and 6 H2O(l) at a temperature of 298 K. Given the following thermodynamic data:[Co(H2O)6]2+(aq) + 4 Cl-(aq) → [CoCl4]2-(aq) + 6 H2O(l) ΔH°= -98.7 kJ mol-1[Co(H2O)6]2+(aq) + 2 Cl-(aq) → [CoCl4]2-(aq) + 4 H2O(l) ΔH°= -65.5 kJ mol-1Assume that the enthalpy of hydration for Cl- (aq) is -364 kJ mol-1.

asked Feb 3 in Chemical thermodynamics by IlaBudd86838 (430 points)

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Calculate the standard enthalpy of reduction for the following reaction: Fe2O3 (s) + 3 H2(g) → 2 Fe(s) + 3 H2O(g)Given: ΔH°f for Fe2O3 (s) = -824.2 kJ/mol ΔH°f for H2O(g) = -241.8 kJ/molΔH°f for Fe(s) = 0 kJ/mol

asked Feb 3 in ThermoChemistry by IssacZapata5 (250 points)

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Calculate the standard enthalpy change for the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) in aqueous solutions. The balanced chemical equation for the reaction is as follows:HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) Given the enthalpy of formation for HCl(aq) is -167.2 kJ/mol, NaOH(aq) is -469.14 kJ/mol, NaCl(aq) is -407.3 kJ/mol, and H2O(l) is -285.83 kJ/mol. The reaction is carried out at standard temperature and pressure.

asked Feb 3 in Chemical thermodynamics by DeborahKelso (490 points)

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Calculate the standard enthalpy change for the vaporization of 25.0 g of water at 100°C, given that the molar enthalpy of vaporization of water is 40.7 kJ/mol. (The molar mass of water is 18.015 g/mol.)

asked Feb 3 in Chemical thermodynamics by FSBCatharine (390 points)

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